尋找1000-2000的閏年

#include<stdio.h>
/*1000-2000之間的閏年*/
int main()
{
 int year,point;
 for(year=1000;year<=2000;year++)
 {
  if(year%4==0)
  {
   if(year%100==0)
   {
    if(year%400==0)
     point=1;
    else
     point=0;
   }
   else
    point=1;
  }
  else
   point=0;
  if(point==1)
   printf("%d ",year);
 }

 return 0;
}