oracle case when 複雜統計SQL

select substr(unitcode,0,6), count(*), --01-- sum(case substr(jqxzcode,0,4) when '0105' then 1 else 0 end) as sharen, sum(case substr(jqxzcode,0,4) when '0109' then 1 else 0 end) as qiangjie, sum(case

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