1005. Spell It Right

1005. Spell It Right (20)

時間限制

400 ms

內存限制

65536 kB

代碼長度限制

16000 B

判題程序

Standard

做者

CHEN, Yue

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10¹⁰⁰).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345

Sample Output:

one five

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner in=new Scanner(System.in);
        String n,str[]=new String [101];
        Integer sum=0;
        n=in.next();
        String s[]={"zero","one","two","three","four","five","six","seven"
                ,"eight","nine"};
        for(int i=0;i<n.length();i++){
            sum=sum+n.charAt(i)-'0';
        }
        
        int len=sum.toString().length();
        while(len!=0){
            if(len!=1){
                System.out.print(s[(int) (sum/Math.pow(10,len-1))]+" ");
            }
            else{
                System.out.print(s[(int) (sum/Math.pow(10,len-1))]);
            }
            sum=(int) (sum%(Math.pow(10,len-1)));
            len--;
        }

    }

}

注意點：10^100int和double都不夠，因此當作字符串讀進來在進行計算

錯誤代碼：

import java.util.Scanner;

public class Main {

  public static void main(String[] args) {
    Scanner in=new Scanner(System.in);
    double n;
    Integer sum=0;
    n=in.nextDouble();
    String s[]={"zero","one","two","three","four","five","six","seven"
        ,"eight","nine"};
    while(n!=0){
      sum=(int) (sum+n%10);
      n=n/10;
    }
    int len=sum.toString().length();
    while(len!=0){
      if(len!=1){
        System.out.print(s[(int) (sum/Math.pow(10,len-1))]+" ");
      }
      else{
        System.out.print(s[(int) (sum/Math.pow(10,len-1))]);
      }
      sum=(int) (sum%(Math.pow(10,len-1)));
      len--;
    }

  }

}

　　結果

參考

http://blog.csdn.net/zhangveni/article/details/50878369