python time和datetime模塊對時間處理方面總結

最近作GPS定位項目,日期處理方面很是多.
python time和datetime模塊對日期處理方面總結

time模塊

• 時間戳 時間

  time.time() # 返回當前時間戳
  
  """result
  1382067918.718
  """

  
  
• strftime 時間

  time.strftime("%Y-%m-%d %X") # 或time.strftime("%Y-%m-%d %H:%M:%S") 返回當前格式化時間
  
  """result
  '2013-10-18 11:47:02'
  """

• 時間戳轉化爲strftime

  time.strftime("%Y-%m-%d %X", time.localtime(1383185294.687))
  
  """result
  '2013-10-31 10:08:14'
  """

• strftime轉換爲時間戳

  time.mktime(time.strptime('2011-05-05 16:37:06', '%Y-%m-%d %X'))
  
  """result
  1304584626.0
  """

datetime模塊

• datetime.datetime類
  1.datetime.datetime對象日期加減

  d1 = datetime.datetime(2013, 06, 01) 
  d2 = datetime.datetime(2013, 10, 18) 
  
  delta = d2 - d1 # datetime.datetime對象日期差返回datetime.timedelta對象
  
  """result
  datetime.timedelta(139)
  """

  2.返回如今的datetime.datetime

  datetime.datetime.now() 
  
  """result
  datetime.datetime(2013, 10, 18, 11, 57, 15, 250000)
  """

  3.datetime.datetime對象屬性

  d = datetime.datetime.now()
  
  d.date() # datetime.date(2013, 10, 18)
  d.time() # datetime.time(12, 0, 54, 140000)
  
  d.weekday() # **返回星期幾
  
  d.year 
  d.month
  d.day
  d.hour
  d.minute
  d.second
  d.microsecond

• datetime.timedelta類
  

d1 = datetime.datetime.now() 
d2 = d1 + datetime.timedelta(hours=10) # datetime.timedelta對象是把時間轉化爲能夠用於datetime.datetime對象加減的時間,而不是已是時間差了

print d2

"""result
datetime.datetime(2013, 10, 18, 22, 0, 54, 140000)
"""

• 把字符串轉化爲datetime
  *******有時候須要把 "2011-12-28 13:11:12"這種時間轉化爲datetime來作時間差
  

  datetime.datetime.strptime("2011-12-28 13:11:12", "%Y-%m-%d %X")
  
  """result
  datetime.datetime(2011, 12, 28, 13, 11, 12)
  """