python開發基礎04-列表、元組、字典操做練習

練習1：

# l1    =  [11,22,33]
# l2   =  [22,33,44]
# a.    獲取內容相同的元素列表
# b.    獲取 l1  中有， l2 中沒有的元素列表
# c.    獲取 l2  中有， l1 中沒有的元素列表
# d.    獲取 l1  和 l2   中內容都不一樣的元素

# l1    =    [11,22,33]
# l2    =    [22,33,44]
# for i in l2:
#     if i not in l1:
#         print(i)
# for i in l1:
#     if i not in l2:
#         print(i)

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練習2：

12345678互相組合爲一個2位數，兩位數值不可重複

 

# count =0
# for i in range(1, 9):
#     for v in range(1, 9):
#         if i !=v:
#             count += 1
# # count = count -8
# print(count)

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練習3：

99乘法表

# for i in range(1,10):
#     string = ""
#     for j in range(1,i+1):
#         string +=str(j) + " * "+str(i) + " = " +str(i*j)+"\t"
#     print(string)

方法1

# for i in range(1,10):
#     for j in range(1,i+1):
#         print(str(j) + " * "+str(i) + " = " +str(i*j)+"\t",end="")
#     print("\n",end="")

# 默認end=\n
# print('alex', end='11')
# print('alex','haifeng','gangniang',sep='11')

方法2

 

練習4：

[1,2,3,4]這裏面的數字兩個組合 多少種不一樣樣的，數字不重複的

# li = [1,2,3,4]
# l =len(li)
# for i in range(0,l-1):
#     for v in range(i+1,l):
#         print(li[i],li[v])

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練習5：

自動計算方案

百錢買小雞

公雞5文錢1只，母雞三文錢一隻，小雞一文錢三隻。如今用100文錢共買了100只雞，

問這100只雞中，公雞，母雞，小雞各是多少隻？ 

for x in range(1,100//5):
    for y in range(1,100//3):
        for z in range(1,100):
            if x + y + z == 100 and 5*x + 3*y + z/3 == 100:
                print(x,y,z)

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練習6：

 查找列表中元素，移除每一個元素的空格，並查找以 a 或 A 開頭 而且以 c 結尾的全部元素。

　　li = ["alec", " aric", "Alex", "Tony", "rain"]

　　tu = ("alec", " aric", "Alex", "Tony", "rain")

　　dic = {'k1': "alex", 'k2': ' aric',"k3": "Alex", "k4": "Tony"}

#!/usr/bin/env python
# -*- coding:utf-8 -*-

li = ["alec", " aric", "Alex", "Tony", "rain"]

for S in li:
S = S.strip()
prefix_a = S.startswith('a')
prefix_A = S.startswith('A')
suffix_c = S.endswith('c')
if prefix_a or prefix_A and suffix_c:
print('要查找的元素:%s' % S)

tu = ("alec", " aric", "Alex", "Tony", "rain")

for S in tu:
S = S.strip()
prefix_a = S.startswith('a')
prefix_A = S.startswith('A')
suffix_c = S.endswith('c')
if prefix_a or prefix_A and suffix_c:
print('要查找的元素:%s' % S)


dic = {'k1': "alex", 'k2': ' aric',"k3": "Alex", "k4": "Tony"}

for S in dic.values():
S = S.strip()
prefix_a = S.startswith('a')
prefix_A = S.startswith('A')
suffix_c = S.endswith('c')
if prefix_a or prefix_A and suffix_c:
print('要查找的元素:%s' % S)

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練習7：

有以下變量，請實現要求的功能

tu = ("alex", [11, 22, {"k1": 'v1', "k2": ["age", "name"], "k3": (11,22,33)}, 44])

• 講述元祖的特性

• 請問 tu 變量中的"k2"對應的值是什麼類型？是否能夠被修改？若是能夠，請在其中添加一個元素 「Seven」

# 元組的一級元素不可被修改增長刪除，有序，可迭代，可切片，可索引，可轉換爲列表。
tu = ("alex", [11, 22, {"k1": 'v1', "k2": ["age", "name"], "k3": (11,22,33)}, 44])
v = tu[1][2]["k2"]
v.append("Seven")
print(tu)

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