[Swift]字符串如何移除奇數位置的字符

背景

字符串如何移除奇數位置的字符

熟悉基本語法，第一個答案給的很簡潔，學習學習

答案

let string = "helloworld"
let newString = string.enumerated().filter({ $0.0 % 2 != 0 }).map({ String($0.element) }).joined()
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1.enumerated

和for in結合起來作遍歷

let string = "helloworld"
for element in string.enumerated() {
    print(element)
}
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能夠獲得的元組(offset, element)

(offset: 0, element: "h")
(offset: 1, element: "e")
(offset: 2, element: "l")
(offset: 3, element: "l")
(offset: 4, element: "o")
(offset: 5, element: "w")
(offset: 6, element: "o")
(offset: 7, element: "r")
(offset: 8, element: "l")
(offset: 9, element: "d")
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2.filter

過濾出奇數位置的數組，每一個元素也是元組(offset, element)

簡寫$0= 元組(offset, element), $0.0 = 元組.offset, $0.1 = 元組.element

let element = string.enumerated().filter({ $0.0 % 2 != 0})
print(element)
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打印

[
(offset: 1, element: "e"), 
(offset: 3, element: "l"), 
(offset: 5, element: "w"), 
(offset: 7, element: "r"), 
(offset: 9, element: "d")]
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3.map

至關於從新對每一個元素作改造，如今每一個數組元素是元組，先把每一個元素改形成字符串

let element = string.enumerated().filter({ $0.0 % 2 != 0}).map({ String($0.element) })
// 或 string.enumerated().filter({ $0.0 % 2 != 0}).map({ String($0.1) })

print(element)
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打印

["e", "l", "w", "r", "d"]
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4. joined

將數組的每一個元素鏈接在一塊兒

let element = string.enumerated().filter({ $0.0 % 2 != 0}).map({ String($0.1) }).joined()
print(element)
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打印

elwrd
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