C++實現牛頓迭代法求解f(x)=0

 #include <iostream> #include <cmath> using namespace std;ios #define f(x) x*x - 8 #define df(x) 2*xspa double EPS = 1e-6;ci double Newton(double xFirst) {    double xSecond;  int iteCount = 0;//迭代次

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