基數排序:先按照最低位進行排序,而後對倒數第二位,以此類推。基於計數排序的基礎上的一種排序方法。屬於穩定排序,時間複雜度O(n),以空間換時間,須要額外的輔助空間。ios
計數排序:假設n個輸入元素的每個都是在0到k區間內的一個整數,其中k是一個整數。運行時間是O(n).數組
計數排序的基本思想是:對每個輸入元素x,肯定小於x的元素個數,從而,直接把x放在它輸出數組中的位置。ide
計數排序僞代碼:測試
CountingSort( A, B, k ) // A:輸入數組; B輸出數組;k 數組元素最大值spa
C[ k ] = { 0 }code
for j = 1 to A.lengthblog
C[A[j]] = C[A[j]] + 1 // 統計數組中某一元素的個數排序
for i = 2 to kio
C[ i ] = C[ i ] + C[ i - 1 ] // 計算數組中小於C[i] 的元素的個數event
for j = A.length downto 1
B[ C[ A[ j ] ] ] = A[ j ] //注:在代碼中,我在這裏是先進行:C[A[j]] = C[A[j]] - 1 , 而後 B[C[A[j]]] = A[j] 。C[A[j]] 的最大值是 A.length,會超出數組B的下標範圍。
C[ A[ j ] ] = C[ A[ j ] ] - 1
計數排序代碼:
#include<iostream> #include<vector> using namespace std; vector<int> CountingSort(vector<int>A,int Max,int Number) //參數: K,最大數值; Number 數組中元素個數 { int max = Max + 1; vector<int> B(Number); vector<int>C(max, 0); for (int i = 0; i < Number; i++) C[A[i]] ++; for (int i = 1; i < max; i++) C[i] += C[i - 1]; for (int j = Number - 1; j >= 0; j--) { C[A[j]]--; B[C[A[j]]] = A[j]; } return B; }
測試代碼:
int main() { vector<int> arry = { 21, 97, 9, 1, 5, 8, 19, 4, 7, 10, 15, 17, 21, 41, 51, 61, 81, 71, 91, 100 }; cout << "排序前" << endl; for (int i = 0; i < 20; i++) cout << arry[i] << " "; cout << endl; int Max = 100; int Number = 20; vector<int>B = CountingSort(arry, Max, Number); for (int i = 0; i < 20; i++) cout << B[i] << " "; cout << endl; cout << "BigThink" << endl; system("pause"); return 0; }
基數排序:
RadixSort(A,d) // A 是輸入數組,d是數組中最大值的位數
for i=1 to d
使用穩定排序法對A中數組的第 i位進行排序
基數排序代碼:
#include<iostream> #include<vector> using namespace std; //求取輸入輸入的最大數字的位數 int GetInt(vector<int>A,int Number) //Number 輸入數組個數 { int d = 1; int Max = A[0]; for (int i = 0; i < Number; i++) if (A[i]>Max) Max = A[i]; while (Max > 10) { Max = Max / 10; d++; } return d; } //基數排序法 vector<int> Radix_Sort(vector<int>A, int Number) //參數 d 最大元素值的位數,Number是數組中元素個數 { int d = GetInt(A, Number); vector<int>B(Number); int radix = 1; for (int i = 1; i <= d; i++) { vector<int> Arry(Number, 0); vector<int> C(10, 0); for (int j = 0; j < Number; j++) { Arry[j] = (A[j] / radix) % 10; C[Arry[j]]++; } for (int j = 1; j < 10; j++) C[j] += C[j - 1]; for (int j = Number - 1; j >= 0; j--) { B[C[Arry[j]]-1] = A[j]; C[Arry[j]]--; } for (int j = 0; j < Number; j++) A[j] = B[j]; radix = radix * 10; } return B; }
測試代碼:
int main() { vector<int>arry = { 3, 7, 9, 14, 25, 52, 36, 78, 95, 28, 11, 32, 24, 250, 620, 140, 8, 91, 20,620 }; cout << "排序前" << endl; for (int i = 0; i < 20; i++) cout << arry[i] << " "; cout << endl; vector<int>B = Radix_Sort(arry, 20); cout << "排序後:" << endl; for (int i = 0; i < 20; i++) cout << B[i] << " "; cout << endl; cout << "BigThink" << endl; system("pause"); return 0; }