bugku | flagphp

1.開腦洞 http://123.206.87.240:8002/flagphp/?hint=1 2.讀源碼得到條件是要求反序列化後的‘ISecer’的值等於$KEY <?php error_reporting(0); include_once("flag.php"); $cookie = $_COOKIE['ISecer']; if(isset($_GET['hi

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