基礎數組 數組合並交叉

標籤（空格分隔）： 未分類

問題：有兩個數組 分別是：

1.["a","b","c"]

2.["1","2","3"]

上面兩個數組合並

造成3.["a","1","b","2","c","3"]

上代碼

var arr1 = ["a", "b", "c"];
            var arr2 = ["1", "2", "3"];
            var arr3 = [], 
            len = arr1.length;
            for (i = 0; i < len; i++) {
    // arr3.splice(len.length - 1, 0, arr1[i], arr2[i]);
                arr3.push(arr1[i]);
                arr3.push(arr2[i]);
            }
            console.log(arr3)

若是要給初始兩個數組添加數據能夠將上面代碼轉變爲一個函數

function newArr(new1, new2) {
            var arr1 = ["a", "b", "c"];
            arr1.push(new1);
            var arr2 = ["1", "2", "3"];
            arr2.push(new2);
            var arr3 = [], len = arr1.length;
            for (i = 0; i < len; i++) {
    // arr3.splice(len.length - 1, 0, arr1[i], arr2[i]);
                arr3.push(arr1[i]);
                arr3.push(arr2[i]);
            }
            return arr3;
        }
        var ne = newArr("aAne", "cTwo");
        console.log(ne);

簡潔法：

function newArr(arr1, arr2) { //定義一個函數，傳兩個參數 arr1第一數組，arr2是第二個數組
                var kong = []; //聲明一個空數組，來放交叉拼接後的數組
                for (var i = 0, l = arr1.length; i < l; i++) {
                    // kong.splice(kong.length,0,arr1[i],arr2[i]);   
                    //數組裏的索引從0開始，kong從1開始，0是要刪除的個數 
                    kong.push(arr1[i]);
                    //console.log(kong);  //a
                    kong.push(arr2[i]);
                    //console.log(kong); //a 1
                }
                return kong;
            }
            var arr = newArr(["a", "b", "c", "e"], ["1", "2", "3", "4"]);

document.write(arr + '<br/>');