1.建立一個數組,判斷數組中是否存在某個值數組
var newarr = [ { num: 1, val: 'ceshi', flag: 'aa' }, { num: 2, val: 'ceshi2', flag: 'aa2' } ] console.log(newarr.filter(item => item.num===2 ))
2.也能夠經過上面方法過濾掉num爲2的留下num爲1的spa
var newarr = [ { num: 1, val: 'ceshi', flag: 'aa' }, { num: 2, val: 'ceshi2', flag: 'aa2' } ] console.log(newarr.filter(item => item.num!=2 ))
3.去掉空數組空字符串、undefined、nullcode
var arr = ['1','2',undefined, '3.jpg',undefined] var newArr = arr.filter(item => item) console.log(newArr) var arr = ['1','2',null, '3.jpg',null] var newArr = arr.filter(item => item) console.log(newArr) >//空字符串裏面不能包含空格 var arr = ['1','2','', '3.jpg',''] var newArr = arr.filter(item => item) console.log(newArr)
4.去掉數組中不符合項blog
var arr = [20,30,50, 96,50] var newArr = arr.filter(item => item>40) console.log(newArr)
5.過濾不符合項字符串
var arr = ['10','12','23','44','42'] var newArr = arr.filter(item => item.indexOf('2')<0) console.log(newArr)
6.數組去重it
var arr = [1, 2, 2, 3, 4, 5, 5, 6, 7, 7,8,8,0,8,6,3,4,56,2]; var arr2 = arr.filter((x, index,self)=>self.indexOf(x)===index) console.log(arr2); //[1, 2, 3, 4, 5, 6, 7, 8, 0, 56]