idea:
1.從後向前找
2.while (tx > ty) tx -= ty; 替爲 % 操做
3.通過循環後,一定只有兩種狀況才truejava
public boolean reachingPoints(int sx, int sy, int tx, int ty) { while (tx > sx && ty > sy){ if (tx > ty) tx %= ty; else ty %= tx; } return sx == tx && sy <= ty && (ty - sy) % sx == 0 || sy == ty && sx <= tx && (tx - sx) % sy == 0; }