Given an array of integers, every element appears twice except for one. Find that single one.app
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?this
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class Solution { public: int singleNumber(vector<int>& nums) { int len=nums.size(); int res = 0; for(int i=0; i<len; i++) { res = res^nums[i]; } return res; } };