SELECT DISTINCT 字段1,字段2... FROM 表名 WHERE 條件 GROUP BY field HAVING 篩選 ORDER BY field LIMIT 限制條數
from where group by select distinct having order by limit
1.找到表:frommysql
2.拿着where指定的約束條件,去文件/表中取出一條條記錄正則表達式
3.將取出的一條條記錄進行分組group by,若是沒有group by,則總體做爲一組sql
4.執行select(去重)windows
5.將分組的結果進行having過濾函數
6.將結果按條件排序:order bypost
7.限制結果的顯示條數編碼
company.employee
員工id id int
姓名 emp_name varchar
性別 sex enum
年齡 age int
入職日期 hire_date date
崗位 post varchar
職位描述 post_comment varchar
薪水 salary double
辦公室 office int
部門編號 depart_id intspa
#建立表
create table employee(
id int not null unique auto_increment,
emp_name varchar(20) not null,
sex enum('male','female') not null default 'male', #大部分是男的
age int(3) unsigned not null default 28,
hire_date date not null,
post varchar(50),
post_comment varchar(100),
salary double(15,2),
office int, #一個部門一個屋子
depart_id int
);code
#查看錶結構
mysql> desc employee;
+--------------+-----------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+-----------------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| emp_name | varchar(20) | NO | | NULL | |
| sex | enum('male','female') | NO | | male | |
| age | int(3) unsigned | NO | | 28 | |
| hire_date | date | NO | | NULL | |
| post | varchar(50) | YES | | NULL | |
| post_comment | varchar(100) | YES | | NULL | |
| salary | double(15,2) | YES | | NULL | |
| office | int(11) | YES | | NULL | |
| depart_id | int(11) | YES | | NULL | |
+--------------+-----------------------+------+-----+---------+----------------+regexp
#插入記錄
#三個部門:教學,銷售,運營
insert into employee(emp_name,sex,age,hire_date,post,salary,office,depart_id) values
('egon','male',18,'20170301','老男孩駐沙河辦事處外交大使',7300.33,401,1), #如下是教學部
('alex','male',78,'20150302','teacher',1000000.31,401,1),
('wupeiqi','male',81,'20130305','teacher',8300,401,1),
('yuanhao','male',73,'20140701','teacher',3500,401,1),
('liwenzhou','male',28,'20121101','teacher',2100,401,1),
('jingliyang','female',18,'20110211','teacher',9000,401,1),
('jinxin','male',18,'19000301','teacher',30000,401,1),
('成龍','male',48,'20101111','teacher',10000,401,1),
('歪歪','female',48,'20150311','sale',3000.13,402,2),#如下是銷售部門
('丫丫','female',38,'20101101','sale',2000.35,402,2),
('丁丁','female',18,'20110312','sale',1000.37,402,2),
('星星','female',18,'20160513','sale',3000.29,402,2),
('格格','female',28,'20170127','sale',4000.33,402,2),
('張野','male',28,'20160311','operation',10000.13,403,3), #如下是運營部門
('程咬金','male',18,'19970312','operation',20000,403,3),
('程咬銀','female',18,'20130311','operation',19000,403,3),
('程咬銅','male',18,'20150411','operation',18000,403,3),
('程咬鐵','female',18,'20140512','operation',17000,403,3)
;
#ps:若是在windows系統中,插入中文字符,select的結果爲空白,能夠將全部字符編碼統一設置成gbk
準備表和記錄
建表和數據準備
#簡單查詢 SELECT id,emp_name,sex,age,hire_date,post,post_comment,salary,office,depart_id FROM employee; SELECT * FROM employee; SELECT emp_name,salary FROM employee; #避免重複DISTINCT SELECT DISTINCT post FROM employee; #經過四則運算查詢 SELECT emp_name, salary*12 FROM employee; SELECT emp_name, salary*12 AS Annual_salary FROM employee; SELECT emp_name, salary*12 Annual_salary FROM employee; #定義顯示格式 CONCAT() 函數用於鏈接字符串 SELECT CONCAT('姓名: ',emp_name,' 年薪: ', salary*12) AS Annual_salary FROM employee; CONCAT_WS() 第一個參數爲分隔符 SELECT CONCAT_WS(':',emp_name,salary*12) AS Annual_salary FROM employee; 結合CASE語句: SELECT ( CASE WHEN emp_name = 'jingliyang' THEN emp_name WHEN emp_name = 'alex' THEN CONCAT(emp_name,'_BIGSB') ELSE concat(emp_name, 'SB') END ) as new_name FROM employee;
小練習:
1 查出全部員工的名字,薪資,格式爲 <名字:egon> <薪資:3000> 2 查出全部的崗位(去掉重複) 3 查出全部員工名字,以及他們的年薪,年薪的字段名爲annual_year
答案
select concat('<名字:',emp_name,'> ','<薪資:',salary,'>') from employee; select distinct depart_id from employee; select emp_name,salary*12 annual_salary from employee;
where字句中可使用:
1. 比較運算符:> < >= <= <> !=
2. between 80 and 100 值在80到100之間
3. in(80,90,100) 值是80或90或100
4. like 'e%'
通配符能夠是%或_,
%表示任意多字符
_表示一個字符
5. 邏輯運算符:在多個條件直接可使用邏輯運算符 and or not
#1:單條件查詢 SELECT emp_name FROM employee WHERE post='sale'; #2:多條件查詢 SELECT emp_name,salary FROM employee WHERE post='teacher' AND salary>10000; #3:關鍵字BETWEEN AND SELECT emp_name,salary FROM employee WHERE salary BETWEEN 10000 AND 20000; SELECT emp_name,salary FROM employee WHERE salary NOT BETWEEN 10000 AND 20000; #4:關鍵字IS NULL(判斷某個字段是否爲NULL不能用等號,須要用IS) SELECT emp_name,post_comment FROM employee WHERE post_comment IS NULL; SELECT emp_name,post_comment FROM employee WHERE post_comment IS NOT NULL; SELECT emp_name,post_comment FROM employee WHERE post_comment=''; 注意''是空字符串,不是null ps: 執行 update employee set post_comment='' where id=2; 再用上條查看,就會有結果了 #5:關鍵字IN集合查詢 SELECT emp_name,salary FROM employee WHERE salary=3000 OR salary=3500 OR salary=4000 OR salary=9000 ; SELECT emp_name,salary FROM employee WHERE salary IN (3000,3500,4000,9000) ; SELECT emp_name,salary FROM employee WHERE salary NOT IN (3000,3500,4000,9000) ; #6:關鍵字LIKE模糊查詢 通配符’%’ SELECT * FROM employee WHERE emp_name LIKE 'eg%'; 通配符’_’ SELECT * FROM employee WHERE emp_name LIKE 'al__';
小練習:
1. 查看崗位是teacher的員工姓名、年齡 2. 查看崗位是teacher且年齡大於30歲的員工姓名、年齡 3. 查看崗位是teacher且薪資在9000-10000範圍內的員工姓名、年齡、薪資 4. 查看崗位描述不爲NULL的員工信息 5. 查看崗位是teacher且薪資是10000或9000或30000的員工姓名、年齡、薪資 6. 查看崗位是teacher且薪資不是10000或9000或30000的員工姓名、年齡、薪資 7. 查看崗位是teacher且名字是jin開頭的員工姓名、年薪
答案
select emp_name,age from employee where post = 'teacher';
select emp_name,age from employee where post='teacher' and age > 30;
select emp_name,age,salary from employee where post='teacher' and salary between 9000 and 10000;
select * from employee where post_comment is not null;
select emp_name,age,salary from employee where post='teacher' and salary in (10000,9000,30000);
select emp_name,age,salary from employee where post='teacher' and salary not in (10000,9000,30000);
select emp_name,salary*12 from employee where post='teacher' and emp_name like 'jin%';
答案
單獨使用GROUP BY關鍵字分組 SELECT post FROM employee GROUP BY post; 注意:咱們按照post字段分組,那麼select查詢的字段只能是post,想要獲取組內的其餘相關信息,須要藉助函數 GROUP BY關鍵字和GROUP_CONCAT()函數一塊兒使用 SELECT post,GROUP_CONCAT(emp_name) FROM employee GROUP BY post;#按照崗位分組,並查看組內成員名 SELECT post,GROUP_CONCAT(emp_name) as emp_members FROM employee GROUP BY post; GROUP BY與聚合函數一塊兒使用 select post,count(id) as count from employee group by post;#按照崗位分組,並查看每一個組有多少人
強調:
若是咱們用unique的字段做爲分組的依據,則每一條記錄自成一組,這種分組沒有意義 多條記錄之間的某個字段值相同,該字段一般用來做爲分組的依據
#強調:聚合函數聚合的是組的內容,如果沒有分組,則默認一組 示例: SELECT COUNT(*) FROM employee; SELECT COUNT(*) FROM employee WHERE depart_id=1; SELECT MAX(salary) FROM employee; SELECT MIN(salary) FROM employee; SELECT AVG(salary) FROM employee; SELECT SUM(salary) FROM employee; SELECT SUM(salary) FROM employee WHERE depart_id=3;
小練習:
1. 查詢崗位名以及崗位包含的全部員工名字 2. 查詢崗位名以及各崗位內包含的員工個數 3. 查詢公司內男員工和女員工的個數 4. 查詢崗位名以及各崗位的平均薪資 5. 查詢崗位名以及各崗位的最高薪資 6. 查詢崗位名以及各崗位的最低薪資 7. 查詢男員工與男員工的平均薪資,女員工與女員工的平均薪資
#題1:分組
mysql> select post,group_concat(emp_name) from employee group by post;
+-----------------------------------------+---------------------------------------------------------+
| post | group_concat(emp_name) |
+-----------------------------------------+---------------------------------------------------------+
| operation | 張野,程咬金,程咬銀,程咬銅,程咬鐵 |
| sale | 歪歪,丫丫,丁丁,星星,格格 |
| teacher | alex,wupeiqi,yuanhao,liwenzhou,jingliyang,jinxin,成龍 |
| 老男孩駐沙河辦事處外交大使 | egon |
+-----------------------------------------+---------------------------------------------------------+
#題目2:
mysql> select post,count(id) from employee group by post;
+-----------------------------------------+-----------+
| post | count(id) |
+-----------------------------------------+-----------+
| operation | 5 |
| sale | 5 |
| teacher | 7 |
| 老男孩駐沙河辦事處外交大使 | 1 |
+-----------------------------------------+-----------+
#題目3:
mysql> select sex,count(id) from employee group by sex;
+--------+-----------+
| sex | count(id) |
+--------+-----------+
| male | 10 |
| female | 8 |
+--------+-----------+
#題目4:
mysql> select post,avg(salary) from employee group by post;
+-----------------------------------------+---------------+
| post | avg(salary) |
+-----------------------------------------+---------------+
| operation | 16800.026000 |
| sale | 2600.294000 |
| teacher | 151842.901429 |
| 老男孩駐沙河辦事處外交大使 | 7300.330000 |
+-----------------------------------------+---------------+
#題目5
mysql> select post,max(salary) from employee group by post;
+-----------------------------------------+-------------+
| post | max(salary) |
+-----------------------------------------+-------------+
| operation | 20000.00 |
| sale | 4000.33 |
| teacher | 1000000.31 |
| 老男孩駐沙河辦事處外交大使 | 7300.33 |
+-----------------------------------------+-------------+
#題目6
mysql> select post,min(salary) from employee group by post;
+-----------------------------------------+-------------+
| post | min(salary) |
+-----------------------------------------+-------------+
| operation | 10000.13 |
| sale | 1000.37 |
| teacher | 2100.00 |
| 老男孩駐沙河辦事處外交大使 | 7300.33 |
+-----------------------------------------+-------------+
#題目七
mysql> select sex,avg(salary) from employee group by sex;
+--------+---------------+
| sex | avg(salary) |
+--------+---------------+
| male | 110920.077000 |
| female | 7250.183750 |
+--------+---------------+
答案
HAVING與WHERE不同的地方在於!!!!!!
#!!!執行優先級從高到低:where > group by > having #1. Where 發生在分組group by以前,於是Where中能夠有任意字段,可是絕對不能使用聚合函數。 #2. Having發生在分組group by以後,於是Having中可使用分組的字段,沒法直接取到其餘字段,可使用聚合函數
mysql> select @@sql_mode;
+--------------------+
| @@sql_mode |
+--------------------+
| ONLY_FULL_GROUP_BY |
+--------------------+
row in set (0.00 sec)
mysql> select * from emp where salary > 100000;
+----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
| id | emp_name | sex | age | hire_date | post | post_comment | salary | office | depart_id |
+----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
| 2 | alex | male | 78 | 2015-03-02 | teacher | NULL | 1000000.31 | 401 | 1 |
+----+------+------+-----+------------+---------+--------------+------------+--------+-----------+
row in set (0.00 sec)
mysql> select post,group_concat(emp_name) from emp group by post having salary > 10000;#錯誤,分組後沒法直接取到salary字段
ERROR 1054 (42S22): Unknown column 'salary' in 'having clause'
mysql> select post,group_concat(emp_name) from emp group by post having avg(salary) > 10000;
+-----------+-------------------------------------------------------+
| post | group_concat(emp_name) |
+-----------+-------------------------------------------------------+
| operation | 程咬鐵,程咬銅,程咬銀,程咬金,張野 |
| teacher | 成龍,jinxin,jingliyang,liwenzhou,yuanhao,wupeiqi,alex |
+-----------+-------------------------------------------------------+
rows in set (0.00 sec)
驗證
小練習:
1. 查詢各崗位內包含的員工個數小於2的崗位名、崗位內包含員工名字、個數 3. 查詢各崗位平均薪資大於10000的崗位名、平均工資 4. 查詢各崗位平均薪資大於10000且小於20000的崗位名、平均工資
#題1:
mysql> select post,group_concat(emp_name),count(id) from employee group by post having count(id) < 2;
+-----------------------------------------+--------------------+-----------+
| post | group_concat(emp_name) | count(id) |
+-----------------------------------------+--------------------+-----------+
| 老男孩駐沙河辦事處外交大使 | egon | 1 |
+-----------------------------------------+--------------------+-----------+
#題目2:
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000;
+-----------+---------------+
| post | avg(salary) |
+-----------+---------------+
| operation | 16800.026000 |
| teacher | 151842.901429 |
+-----------+---------------+
#題目3:
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000;
+-----------+--------------+
| post | avg(salary) |
+-----------+--------------+
| operation | 16800.026000 |
+-----------+--------------+
答案
按單列排序 SELECT * FROM employee ORDER BY salary; SELECT * FROM employee ORDER BY salary ASC; SELECT * FROM employee ORDER BY salary DESC; 按多列排序:先按照age排序,若是年紀相同,則按照薪資排序 SELECT * from employee ORDER BY age, salary DESC;
小練習:
1. 查詢全部員工信息,先按照age升序排序,若是age相同則按照hire_date降序排序 2. 查詢各崗位平均薪資大於10000的崗位名、平均工資,結果按平均薪資升序排列 3. 查詢各崗位平均薪資大於10000的崗位名、平均工資,結果按平均薪資降序排列
#題目1
mysql> select * from employee ORDER BY age asc,hire_date desc;
#題目2
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc;
+-----------+---------------+
| post | avg(salary) |
+-----------+---------------+
| operation | 16800.026000 |
| teacher | 151842.901429 |
+-----------+---------------+
#題目3
mysql> select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc;
+-----------+---------------+
| post | avg(salary) |
+-----------+---------------+
| teacher | 151842.901429 |
| operation | 16800.026000 |
+-----------+---------------+
答案
示例: SELECT * FROM employee ORDER BY salary DESC LIMIT 3; #默認初始位置爲0 SELECT * FROM employee ORDER BY salary DESC LIMIT 0,5; #從第0開始,即先查詢出第一條,而後包含這一條在內日後查5條 SELECT * FROM employee ORDER BY salary DESC LIMIT 5,5; #從第5開始,即先查詢出第6條,而後包含這一條在內日後查5條
小練習:
1. 分頁顯示,每頁5條
mysql> select * from employee limit 0,5;
+----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
| id | emp_name | sex | age | hire_date | post | post_comment | salary | office | depart_id |
+----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
| 1 | egon | male | 18 | 2017-03-01 | 老男孩駐沙河辦事處外交大使 | NULL | 7300.33 | 401 | 1 |
| 2 | alex | male | 78 | 2015-03-02 | teacher | | 1000000.31 | 401 | 1 |
| 3 | wupeiqi | male | 81 | 2013-03-05 | teacher | NULL | 8300.00 | 401 | 1 |
| 4 | yuanhao | male | 73 | 2014-07-01 | teacher | NULL | 3500.00 | 401 | 1 |
| 5 | liwenzhou | male | 28 | 2012-11-01 | teacher | NULL | 2100.00 | 401 | 1 |
+----+-----------+------+-----+------------+-----------------------------------------+--------------+------------+--------+-----------+
rows in set (0.00 sec)
mysql> select * from employee limit 5,5;
+----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
| id | emp_name | sex | age | hire_date | post | post_comment | salary | office | depart_id |
+----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
| 6 | jingliyang | female | 18 | 2011-02-11 | teacher | NULL | 9000.00 | 401 | 1 |
| 7 | jinxin | male | 18 | 1900-03-01 | teacher | NULL | 30000.00 | 401 | 1 |
| 8 | 成龍 | male | 48 | 2010-11-11 | teacher | NULL | 10000.00 | 401 | 1 |
| 9 | 歪歪 | female | 48 | 2015-03-11 | sale | NULL | 3000.13 | 402 | 2 |
| 10 | 丫丫 | female | 38 | 2010-11-01 | sale | NULL | 2000.35 | 402 | 2 |
+----+------------+--------+-----+------------+---------+--------------+----------+--------+-----------+
rows in set (0.00 sec)
mysql> select * from employee limit 10,5;
+----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
| id | emp_name | sex | age | hire_date | post | post_comment | salary | office | depart_id |
+----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
| 11 | 丁丁 | female | 18 | 2011-03-12 | sale | NULL | 1000.37 | 402 | 2 |
| 12 | 星星 | female | 18 | 2016-05-13 | sale | NULL | 3000.29 | 402 | 2 |
| 13 | 格格 | female | 28 | 2017-01-27 | sale | NULL | 4000.33 | 402 | 2 |
| 14 | 張野 | male | 28 | 2016-03-11 | operation | NULL | 10000.13 | 403 | 3 |
| 15 | 程咬金 | male | 18 | 1997-03-12 | operation | NULL | 20000.00 | 403 | 3 |
+----+-----------+--------+-----+------------+-----------+--------------+----------+--------+-----------+
rows in set (0.00 sec)
答案
SELECT * FROM employee WHERE emp_name REGEXP '^ale'; SELECT * FROM employee WHERE emp_name REGEXP 'on$'; SELECT * FROM employee WHERE emp_name REGEXP 'm{2}'; 小結:對字符串匹配的方式 WHERE emp_name = 'egon'; WHERE emp_name LIKE 'yua%'; WHERE emp_name REGEXP 'on$';
小練習:
查看全部員工中名字是jin開頭,n或者g結果的員工信息
答案select * from employee where emp_name regexp '^jin.*[gn]$';