MySQL記錄操做mysql
MySQL數據操做: DML正則表達式
在MySQL管理軟件中,能夠經過SQL語句中的DML語言來實現數據的操做,包括sql
1. 插入完整數據(順序插入) 語法一: INSERT INTO 表名(字段1,字段2,字段3…字段n) VALUES(值1,值2,值3…值n); 語法二: INSERT INTO 表名 VALUES (值1,值2,值3…值n); 2. 指定字段插入數據 語法: INSERT INTO 表名(字段1,字段2,字段3…) VALUES (值1,值2,值3…); 3. 插入多條記錄 語法: INSERT INTO 表名 VALUES (值1,值2,值3…值n), (值1,值2,值3…值n), (值1,值2,值3…值n); 4. 插入查詢結果 語法: INSERT INTO 表名(字段1,字段2,字段3…字段n) SELECT (字段1,字段2,字段3…字段n) FROM 表2 WHERE …;
語法: UPDATE 表名 SET 字段1=值1, 字段2=值2, WHERE CONDITION; 示例: UPDATE mysql.user SET password=password(‘123’) where user=’root’ and host=’localhost’;
語法: DELETE FROM 表名 WHERE CONITION; 示例: DELETE FROM mysql.user WHERE password=’’; 練習: 更新MySQL root用戶密碼爲mysql123 刪除除從本地登陸的root用戶之外的全部用戶
from where group by select distinct having order by limit
1.找到表:fromwindows
2.拿着where指定的約束條件,去文件/表中取出一條條記錄函數
3.將取出的一條條記錄進行分組group by,若是沒有group by,則總體做爲一組post
4.執行select(去重)編碼
5.將分組的結果進行having過濾code
6.將結果按條件排序:order by排序
7.限制結果的顯示條數rem
#建立表 create table employee( id int not null unique auto_increment, emp_name varchar(20) not null, sex enum('male','female') not null default 'male', #大部分是男的 age int(3) unsigned not null default 28, hire_date date not null, post varchar(50), post_comment varchar(100), salary double(15,2), office int, #一個部門一個屋子 depart_id int ); #查看錶結構 mysql> desc employee; +--------------+-----------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+-----------------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | emp_name | varchar(20) | NO | | NULL | | | sex | enum('male','female') | NO | | male | | | age | int(3) unsigned | NO | | 28 | | | hire_date | date | NO | | NULL | | | post | varchar(50) | YES | | NULL | | | post_comment | varchar(100) | YES | | NULL | | | salary | double(15,2) | YES | | NULL | | | office | int(11) | YES | | NULL | | | depart_id | int(11) | YES | | NULL | | +--------------+-----------------------+------+-----+---------+----------------+ #插入記錄 #三個部門:教學,銷售,運營 insert into employee(emp_name,sex,age,hire_date,post,salary,office,depart_id) values ('egon','male',18,'20170301','辦事處',7300.33,401,1), #如下是教學部 ('anwen','male',78,'20150302','teacher',1000000.31,401,1), ('wudi','male',81,'20130305','teacher',8300,401,1), ('yuanhao','male',73,'20140701','teacher',3500,401,1), ('liwen','male',28,'20121101','teacher',2100,401,1), ('jingliyang','female',18,'20110211','teacher',9000,401,1), ('jinxin','male',18,'19000301','teacher',30000,401,1), ('成龍','male',48,'20101111','teacher',10000,401,1), ('歪歪','female',48,'20150311','sale',3000.13,402,2),#如下是銷售部門 ('丫丫','female',38,'20101101','sale',2000.35,402,2), ('丁丁','female',18,'20110312','sale',1000.37,402,2), ('星星','female',18,'20160513','sale',3000.29,402,2), ('格格','female',28,'20170127','sale',4000.33,402,2), ('張xx','male',28,'20160311','operation',10000.13,403,3), #如下是運營部門 ('程咬金','male',18,'19970312','operation',20000,403,3), ('程咬銀','female',18,'20130311','operation',19000,403,3), ('程咬銅','male',18,'20150411','operation',18000,403,3), ('程咬鐵','female',18,'20140512','operation',17000,403,3) ; #ps:若是在windows系統中,插入中文字符,select的結果爲空白,能夠將全部字符編碼統一設置成gbk 準備表和記錄
#簡單查詢 SELECT id,emp_name,sex,age,hire_date,post,post_comment,salary,office,depart_id FROM employee; SELECT * FROM employee; SELECT emp_name,salary FROM employee; #避免重複DISTINCT SELECT DISTINCT post FROM employee; #經過四則運算查詢 SELECT emp_name, salary*12 FROM employee; SELECT emp_name, salary*12 AS Annual_salary FROM employee; SELECT emp_name, salary*12 Annual_salary FROM employee; #定義顯示格式 CONCAT() 函數用於鏈接字符串 SELECT CONCAT('姓名: ',emp_name,' 年薪: ', salary*12) AS Annual_salary FROM employee; CONCAT_WS() 第一個參數爲分隔符 SELECT CONCAT_WS(':',emp_name,salary*12) AS Annual_salary FROM employee; 結合CASE語句: SELECT ( CASE WHEN emp_name = 'jingliyang' THEN emp_name WHEN emp_name = 'alex' THEN CONCAT(emp_name,'_BIGSB') ELSE concat(emp_name, 'SB') END ) as new_name FROM employee;
小練習:
1 查出全部員工的名字,薪資,格式爲 <名字:egon> <薪資:3000> 2 查出全部的崗位(去掉重複) 3 查出全部員工名字,以及他們的年薪,年薪的字段名爲annual_year select concat('<名字:',emp_name,'> ','<薪資:',salary,'>') from employee; select distinct depart_id from employee; select emp_name,salary*12 annual_salary from employee;
where字句中能夠使用:
#1:單條件查詢 SELECT emp_name FROM employee WHERE post='sale'; #2:多條件查詢 SELECT emp_name,salary FROM employee WHERE post='teacher' AND salary>10000; #3:關鍵字BETWEEN AND SELECT emp_name,salary FROM employee WHERE salary BETWEEN 10000 AND 20000; SELECT emp_name,salary FROM employee WHERE salary NOT BETWEEN 10000 AND 20000; #4:關鍵字IS NULL(判斷某個字段是否爲NULL不能用等號,須要用IS) SELECT emp_name,post_comment FROM employee WHERE post_comment IS NULL; SELECT emp_name,post_comment FROM employee WHERE post_comment IS NOT NULL; SELECT emp_name,post_comment FROM employee WHERE post_comment=''; 注意''是空字符串,不是null ps: 執行 update employee set post_comment='' where id=2; 再用上條查看,就會有結果了 #5:關鍵字IN集合查詢 SELECT emp_name,salary FROM employee WHERE salary=3000 OR salary=3500 OR salary=4000 OR salary=9000 ; SELECT emp_name,salary FROM employee WHERE salary IN (3000,3500,4000,9000) ; SELECT emp_name,salary FROM employee WHERE salary NOT IN (3000,3500,4000,9000) ; #6:關鍵字LIKE模糊查詢 通配符’%’ SELECT * FROM employee WHERE emp_name LIKE 'eg%'; 通配符’_’ SELECT * FROM employee WHERE emp_name LIKE 'al__';
小練習:
1. 查看崗位是teacher的員工姓名、年齡 2. 查看崗位是teacher且年齡大於30歲的員工姓名、年齡 3. 查看崗位是teacher且薪資在9000-1000範圍內的員工姓名、年齡、薪資 4. 查看崗位描述不爲NULL的員工信息 5. 查看崗位是teacher且薪資是10000或9000或30000的員工姓名、年齡、薪資 6. 查看崗位是teacher且薪資不是10000或9000或30000的員工姓名、年齡、薪資 7. 查看崗位是teacher且名字是jin開頭的員工姓名、年薪 select emp_name,age from employee where post = 'teacher'; select emp_name,age from employee where post='teacher' and age > 30; select emp_name,age,salary from employee where post='teacher' and salary between 9000 and 10000; select * from employee where post_comment is not null; select emp_name,age,salary from employee where post='teacher' and salary in (10000,9000,30000); select emp_name,age,salary from employee where post='teacher' and salary not in (10000,9000,30000); select emp_name,salary*12 from employee where post='teacher' and emp_name like 'jin%';
單獨使用GROUP BY關鍵字分組 SELECT post FROM employee GROUP BY post; 注意:咱們按照post字段分組,那麼select查詢的字段只能是post,想要獲取組內的其餘相關信息,須要藉助函數 GROUP BY關鍵字和GROUP_CONCAT()函數一塊兒使用 SELECT post,GROUP_CONCAT(emp_name) FROM employee GROUP BY post;#按照崗位分組,並查看組內成員名 SELECT post,GROUP_CONCAT(emp_name) as emp_members FROM employee GROUP BY post; GROUP BY與聚合函數一塊兒使用 select post,count(id) as count from employee group by post;#按照崗位分組,並查看每一個組有多少人 強調: 若是咱們用unique的字段做爲分組的依據,則每一條記錄自成一組,這種分組沒有意義 多條記錄之間的某個字段值相同,該字段一般用來做爲分組的依據
#強調:聚合函數聚合的是組的內容,如果沒有分組,則默認一組 示例: SELECT COUNT(*) FROM employee; SELECT COUNT(*) FROM employee WHERE depart_id=1; SELECT MAX(salary) FROM employee; SELECT MIN(salary) FROM employee; SELECT AVG(salary) FROM employee; SELECT SUM(salary) FROM employee; SELECT SUM(salary) FROM employee WHERE depart_id=3;
小練習:
1. 查詢崗位名以及崗位包含的全部員工名字 2. 查詢崗位名以及各崗位內包含的員工個數 3. 查詢公司內男員工和女員工的個數 4. 查詢崗位名以及各崗位的平均薪資 5. 查詢崗位名以及各崗位的最高薪資 6. 查詢崗位名以及各崗位的最低薪資 7. 查詢男員工與男員工的平均薪資,女員工與女員工的平均薪資 #題1:分組 mysql> select post,group_concat(emp_name) from employee group by post; #題目2: mysql> select post,count(id) from employee group by post; #題目3: mysql> select sex,count(id) from employee group by sex; #題目4: mysql> select post,avg(salary) from employee group by post; #題目5 mysql> select post,max(salary) from employee group by post; #題目6 mysql> select post,min(salary) from employee group by post; #題目七 mysql> select sex,avg(salary) from employee group by sex;
HAVING與WHERE不同的地方在於!!!!!!
#!!!執行優先級從高到低:where > group by > having #1. Where 發生在分組group by以前,於是Where中能夠有任意字段,可是絕對不能使用聚合函數。 #2. Having發生在分組group by以後,於是Having中能夠使用分組的字段,沒法直接取到其餘字段,能夠使用聚合函數
select * from emp where salary > 100000; mysql> select post,group_concat(emp_name) from emp group by post having salary > 10000;#錯誤,分組後沒法直接取到salary字段 ERROR 1054 (42S22): Unknown column 'salary' in 'having clause' mysql> select post,group_concat(emp_name) from emp group by post having avg(salary) > 10000;
小練習:
1. 查詢各崗位內包含的員工個數小於2的崗位名、崗位內包含員工名字、個數 3. 查詢各崗位平均薪資大於10000的崗位名、平均工資 4. 查詢各崗位平均薪資大於10000且小於20000的崗位名、平均工資 select post,group_concat(emp_name),count(id) from employee group by post having count(id) < 2; select post,avg(salary) from employee group by post having avg(salary) > 10000; select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000;
按單列排序 SELECT * FROM employee ORDER BY salary; SELECT * FROM employee ORDER BY salary ASC; SELECT * FROM employee ORDER BY salary DESC; 按多列排序:先按照age排序,若是年紀相同,則按照薪資排序 SELECT * from employee ORDER BY age, salary DESC;
小練習:
1. 查詢全部員工信息,先按照age升序排序,若是age相同則按照hire_date降序排序 2. 查詢各崗位平均薪資大於10000的崗位名、平均工資,結果按平均薪資升序排列 3. 查詢各崗位平均薪資大於10000的崗位名、平均工資,結果按平均薪資降序排列 select * from employee ORDER BY age asc,hire_date desc; select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc; select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc;
示例: SELECT * FROM employee ORDER BY salary DESC LIMIT 3; #默認初始位置爲0 SELECT * FROM employee ORDER BY salary DESC LIMIT 0,5; #從第0開始,即先查詢出第一條,而後包含這一條在內日後查5條 SELECT * FROM employee ORDER BY salary DESC LIMIT 5,5; #從第5開始,即先查詢出第6條,而後包含這一條在內日後查5條
小練習:
select * from employee limit 0,5; select * from employee limit 5,5; select * from employee limit 10,5;
SELECT * FROM employee WHERE emp_name REGEXP '^ale'; SELECT * FROM employee WHERE emp_name REGEXP 'on$'; SELECT * FROM employee WHERE emp_name REGEXP 'm{2}'; 小結:對字符串匹配的方式 WHERE emp_name = 'egon'; WHERE emp_name LIKE 'yua%'; WHERE emp_name REGEXP 'on$';