Digits Are Not Just Characters
http://codeforces.com/gym/102082/attachments/download/8301/asia-yokohama-regional-contest-2018-en.pdf 重新寫一個數組存字母和數字，因爲最多9位數將字母的ascll+10^10那麼一定大於9個連續數字，連續的數字字符用一個zu[]存下，那麼就可以直接將兩個數組順序比較了。如果是一個字符一個字符比較會
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相關文章
- 1. Smart cities are just around the corner
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