計算兩日期之間的工做天數, 過濾休息日

import datetime
# 計算兩個日期之間的工做日數,非天數.
class workDays():
    def __init__(self, start_date, end_date, days_off=None):
        """days_off:休息日,默認週六日, 以0(星期一)開始,到6(星期天)結束, 傳入tupple
        沒有包含法定節假日,
        """
        self.start_date = start_date
        self.end_date = end_date
        self.days_off = days_off
        if self.start_date > self.end_date:
            self.start_date,self.end_date = self.end_date, self.start_date
        if days_off is None:
            self.days_off = 5,6
        # 每週工做日列表
        self.days_work = [x for x in range(7) if x not in self.days_off]

    def workDays(self):
        """實現工做日的 iter, 從start_date 到 end_date , 若是在工做日內,yield 日期
        """
        # 還沒排除法定節假日
        tag_date = self.start_date
        while True:
            if tag_date > self.end_date:
                break
            if tag_date.weekday() in self.days_work:
                yield tag_date
            tag_date += datetime.timedelta(days=1)

    def daysCount(self):
        """工做日統計,返回數字"""
        return len(list(self.workDays()))

    def weeksCount(self, day_start=0):
        """統計全部跨越的週數,返回數字
        默認周從星期一開始計算
        """
        day_nextweek = self.start_date
        while True:
            if day_nextweek.weekday() == day_start:
                break
            day_nextweek += datetime.timedelta(days=1)
        # 區間在一週內
        if day_nextweek > self.end_date:
            return 1
        weeks = ((self.end_date - day_nextweek).days + 1)/7
        weeks = int(weeks)
        if ((self.end_date - day_nextweek).days + 1)%7:
            weeks += 1
        if self.start_date < day_nextweek:
            weeks += 1
        return weeks

測試:

a=datetime.date(2014,5,15)
b=datetime.date(2014,5,13)
work = workDays(a,b)
for day in work.workDays():
    print day,"星期",day.weekday()+1
print "總天數:", work.daysCount()
print "總週數:", work.weeksCount(day_start=6)

結果:

2014-05-13 星期 2
2014-05-14 星期 3
2014-05-15 星期 4
總天數: 3
總週數: 1