思路:首先將JSON格式的數據轉換成JSONObject,而後將JSONObject轉換成Java的實體類(其中類屬性包括List等類型)java
Java實體類:json
SearchFilter 類
1 public class SearchFilter { 2 private String groupOp; 3 4 private List<SearchRule> rules; 5 6 public String getGroupOp() { 7 return groupOp; 8 } 9 10 public void setGroupOp(String groupOp) { 11 this.groupOp = groupOp; 12 } 13 14 public List<SearchRule> getRules() { 15 return rules; 16 } 17 18 public void setRules(List<SearchRule> rules) { 19 this.rules = rules; 20 }
SearchRule 類:
1 public class SearchRule { 2 private String field; 3 private String op; 4 private String data; 5 public String getField() { 6 return field; 7 } 8 public void setField(String field) { 9 this.field = field; 10 } 11 public String getOp() { 12 return op; 13 } 14 public void setOp(String op) { 15 this.op = op; 16 } 17 public String getData() { 18 return data; 19 } 20 public void setData(String data) { 21 this.data = data; 22 } 23 24 25 }
1 //導入的package 2 import com.fasterxml.jackson.databind.ObjectMapper; 3 import net.sf.json.JSONArray; 4 import net.sf.json.JSONObject;
解析JSon格式字符串的方法數組
1 public SearchFilter jsonToSearchFilter(String filters) { 2 SearchFilter searchFilter = null; 3 try { 4 JSONObject jsonobject = JSONObject.fromObject(filters);//將json格式的字符串轉換成JSONObject 對象 5 JSONArray array = jsonobject.getJSONArray("rules"); //若是json格式的字符串裏含有數組格式的屬性,將其轉換成JSONArray,以方便後面轉換成對應的實體 6 List<SearchRule> rules = new ArrayList<SearchRule>(); 7 for (int i = 0; i < array.size(); i++) { 8 JSONObject object = (JSONObject) array.get(i); //將array中的數據進行逐條轉換 9 SearchRule rule = (SearchRule) JSONObject.toBean(object, SearchRule.class); //經過JSONObject.toBean()方法進行對象間的轉換 10 rules.add(rule); 11 } 12 String groupOp = jsonobject.getString("groupOp"); //簡單的直接獲取值 13 searchFilter = new SearchFilter(); //對SearchFilter對象進行組裝 14 searchFilter.setGroupOp(groupOp); 15 searchFilter.setRules(rules); 16 } catch (Exception e) { 17 System.out.println("filters=" + filters.toString() + ".json轉換成實體類出錯"); 18 e.printStackTrace(); 19 } 20 return searchFilter; 21 }
這裏只進行了SearchFilter類中list<SearchRule>rule屬性的對象轉換,由於它是一個SearchRule對象數組,須要單獨拿出來進行json轉換成對象,若是直接對filter進行 SearchFilter進行實體轉換會報錯。若是對象中不含有list,array,map等集合,能夠像8-9行同樣進行對象轉換。app
測試:測試
1 public static void main(String[] args) { 2 UserMgmtController con = new UserMgmtController(); 3 String filters="{\"groupOp\": \"OR\",\"rules\": [{\"field\": \"realname\",\"op\": \"eq\","+ 4 "\"data\": \"1234\"},{\"field\": \"cityCode\",\"op\": \"ne\",\"data\": \"5678\"}]}"; 5 SearchFilter searchFilter =con.jsonToSearchFilter(filters); 6 System.out.println("gop="+searchFilter.getGroupOp()+" rules.size="+searchFilter.getRules().size()); 7 }
結果:gop=OR rules.size=2
將java對象轉換成json格式:
1 //將Object 對象轉換成 json 2 public String objectToJson(Object obj) { 3 ObjectMapper mapper = new ObjectMapper(); 4 // Convert object to JSON string 5 String jsonStr = null; 6 try { 7 jsonStr = mapper.writeValueAsString(obj); 8 } catch (IOException e) { 9 log.error(obj + "entity 轉換成 json出錯", e); 10 e.printStackTrace(); 11 System.out.println("entity 轉換成 json出錯"); 12 } 13 return jsonStr; 14 }
將Object 轉換成json字符串時,默認使用用是的駝峯方式,若是不想使用駝峯則能夠增長紅色部分設置,帶下劃線的也能夠原樣輸出:this
1 public String objectToJson(Object obj){ 2 ObjectMapper mapper = new ObjectMapper(); 3 String json =null; 4 try { 5 PropertyNamingStrategy.PascalCaseStrategy pp = new PropertyNamingStrategy.PascalCaseStrategy(); 6 mapper.setPropertyNamingStrategy(pp); 7 json = mapper.writeValueAsString(obj); 8 } catch (JsonProcessingException e) { 9 log.error("json對象轉換失敗",e); 10 e.printStackTrace(); 11 } 12 return json; 13 }
結果:spa
"UpLoadDateTime":"2017-09-25 10:51:41","OrganizationId":"B3EA5A4D-7C60-4C21-AF09-494890467C34" ,"Test_Code":""