C++代碼ios
1 #include <boost/lexical_cast.hpp> 2 #include <iostream> 3 int main() 4 { 5 using boost::lexical_cast; 6 int a = lexical_cast<int>("123"); 7 double b = lexical_cast<double>("123.12"); 8 std::cout<<a<<std::endl 9 std::cout<<b<<std::endl; 10 return 0; 11 }
C++代碼spa
1 #include <boost/lexical_cast.hpp> 2 #include <string> 3 #include <iostream> 4 int main() 5 { 6 using std::string; 7 const double d = 123.12; 8 string s = boost::lexical_cast<string>(d); 9 std::cout<<s<<std::endl; 10 return 0; 11 }
若是轉換髮生了意外,lexical_cast會拋出一個bad_lexical_cast異常,所以程序中須要對其進行捕捉。code
C++代碼blog
1 #include <boost/lexical_cast.hpp> 2 #include <iostream> 3 int main() 4 { 5 using std::cout; 6 using std::endl; 7 int i; 8 try 9 { 10 i = boost::lexical_cast<int>("xyz"); 11 } 12 catch(boost::bad_lexical_cast& e) 13 { 14 cout<<e.what()<<endl; 15 return 1; 16 } 17 cout<<i<<endl; 18 return 0; 19 }
顯然「xyz」並不能轉換爲一個int類型的數值,因而拋出異常,捕捉後輸出「bad lexical cast: source type value could not be interpreted as target」這樣的信息。字符串
lexical_cast依賴於字符流std::stringstream,其原理至關簡單:把源類型讀入到字符流中,再寫到目標類型中,就大功告成。get