連續整數的c源代碼

#include<iostream> using namespace std; int main(void) { int i=1; int n; cout<<"趁時間沒發覺"<<endl; cin>>n; int max = n; int g = 1; int N = n/2+1; int * f = new int[N+1]; f[1] = 1; i = 1;  int i1 = i; int sum = f[1]; while(1) {   g = 1;   if(sum>max)   {      g = 0;   }   if(sum == max)   {   for(int k=i1; k<=i; k++)   cout<<f[k]<<" ";   cout<<endl;   g = 0;   }    if(g && i<N)   {      i++; f[i] = i; sum = sum + f[i];continue;   }   else   {      i1++;  i = i1;  f[i] = i;  sum = f[i];  if(i1<N)  continue;  else  break;   } }    return 0; }