Given a sorted integer array without duplicates, return the summary of its ranges.數組
For example, given [0,1,2,4,5,7]
, return ["0->2","4->5","7"]
.code
輸入一個排序好的整數數組,輸出數組中連續數字的範圍的數組排序
/** * @param {number[]} nums * @return {string[]} */ var summaryRanges = function(nums) { let rst = [], tem = nums[0]; nums.map((num, i) => { if (nums[i+1] - num !== 1) { num === tem ? rst.push(`${num}`): rst.push(`${tem}->${num}`); tem = nums[i+1] } }); return rst; };
這是個人解法,不知道有沒有有更好更快的實現string