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【Codeforces Round 57 (Rated for Div. 2)】Polygon for the Angle
時間 2021-01-13
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題意:給出一個角度,找出一個最小的正多邊形,使得某三個頂點連成的角等於已給角度,輸出這個正多邊形 思路:每一個正多邊形都有他的外接圓和內切圓,並且兩個圓的圓心是相同的 圓心角是圓周角的二倍,圓心角從 360/n 開始取值,一直取到(n-2)× (360/n) 注意179度是可以由360邊形構造出來的 代碼: #include <iostream> #include <cstdio> #includ
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相關文章
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C. Polygon for the Angle Educational Codeforces Round 57 (Rated for Div. 2)
2.
Educational Codeforces Round 57 (Rated for Div. 2)
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