A car moves from point A to point B at speed v meters per second. The action takes place on the X-axis. At the distance d meters from A there are traffic lights. Starting from time 0, for the first g seconds the green light is on, then for the following r seconds the red light is on, then again the green light is on for the g seconds, and so on.ios
The car can be instantly accelerated from 0 to v and vice versa, can instantly slow down from the v to 0. Consider that it passes the traffic lights at the green light instantly. If the car approaches the traffic lights at the moment when the red light has just turned on, it doesn't have time to pass it. But if it approaches the traffic lights at the moment when the green light has just turned on, it can move. The car leaves point A at the time 0.app
What is the minimum time for the car to get from point A to point B without breaking the traffic rules?ide
提示:spa
1.注意「If the car approaches the traffic lights at the moment when the red light has just turned on, it doesn't have time to pass it」。code
2.只要不是等待綠燈,都全速行駛blog
AC Code:ci
1 #include <iostream> 2 #include <string> 3 #include <algorithm> 4 #include <map> 5 #include <vector> 6 #include <cstdio> 7 #include <cmath> 8 #include <cstring> 9 using namespace std; 10 11 int main() 12 { 13 double l, d, v, g, r; 14 double ans; 15 const double eps = 1e-8; 16 while(cin >> l >> d >> v >> g >> r) 17 { 18 int t = d / v / (g + r); 19 double a = d / v - t * (g + r); 20 if(fabs(a - g) < eps) 21 ans = l / v + r; 22 else if(a < g) 23 ans = l / v; 24 else 25 ans = g + r - a + l / v; 26 printf("%.8lf\n", ans); 27 } 28 return 0; 29 }