org json 和 fast json 摻雜使用引發的錯誤

1. 取值的不一樣

當所取得key不存在時：

org json 會拋異常

fast json 會返回null

示例：

com.alibaba.fastjson.JSONObject fastJson = new com.alibaba.fastjson.JSONObject();

String name = fastJson.getString("name");

// fastJson 正常輸出 name:null

System.out.println("name:" + name);

 

org.json.JSONObject orgJson = new org.json.JSONObject();

//拋出異常：org.json.JSONException: JSONObject["name"] not found.

name = orgJson.getString("name");

System.out.println("name:" + name);

 

2. fast json 中 put org json

該操做異常，會放入空json

示例：

org.json.JSONObject orgJsonAddress = new org.json.JSONObject();

orgJsonAddress.put("country", "China");

orgJsonAddress.put("province", "Henan");

orgJsonAddress.put("city", "Zhengzhou");

 

com.alibaba.fastjson.JSONObject fastJson = new com.alibaba.fastjson.JSONObject();

fastJson.put("name", "Qingjiang Li");

fastJson.put("sex", 1);

fastJson.put("address", orgJsonAddress);

System.out.println(fastJson.toJSONString());

 

異常輸出：

{

"address": {},

"sex": 1,

"name": "Qingjiang Li"

}

 

 

3. org json 中 put fast json

該操做正常

示例：

com.alibaba.fastjson.JSONObject fastJsonAddress = new com.alibaba.fastjson.JSONObject();

fastJsonAddress.put("country", "China");

fastJsonAddress.put("province", "Henan");

fastJsonAddress.put("city", "Zhengzhou");

 

org.json.JSONObject orgJson = new org.json.JSONObject();

orgJson.put("name", "Qingjiang Li");

orgJson.put("sex", 1);

orgJson.put("address", fastJsonAddress);

System.out.println(orgJson.toString());

 

輸出正常：

{

"address": {

"country": "China",

"province": "Henan",

"city": "Zhengzhou"

},

"sex": 1,

"name": "Qingjiang Li"

}

 

 

結論：

　　在項目中，儘量使用同一個種 JSON，若是不得已須要都使用，那麼使用時請注意，避免因習慣，引發錯誤。