PAT-乙-1027 1027 打印沙漏 (20 分)

代碼 #include <iostream> using namespace std; int main(){ int n; char c; cin>>n>>c; int sum = 1; int lastSum = 1; int pos = 1; int tmp = 3; while(n>=sum){ lastSum = sum; sum += tmp*2;
相關文章
相關標籤/搜索