1. 分別使用for循環,while循環,do循環求1到100之間全部能被3整除的整數的和。(知識點:循環語句)java
package doom3; public class thefourweekworks1_0 { public static void main(String[] args) { // TODO Auto-generated method stub int i = 1; int sum = 0; for (i = 1; i <= 100; i++) { if (i % 3 == 0) sum += i; } System.out.print(sum); } }
package doom3; public class thefourweekworks1_1 { public static void main(String[] args) { // TODO Auto-generated method stub int i=1; int sum=0; while(i<=100){ if(i%3==0) sum+=i; i++; } System.out.print(sum); } }
package doom3; public class thefourweekworks1_2 { public static void main(String[] args) { // TODO Auto-generated method stub int i = 1; int sum = 0; do { if (i % 3 == 0) sum += i; i++; } while (i <= 100); System.out.print(sum); } }
2. 輸出0-9之間的數,可是不包括5。(知識點:條件、循環語句)3d
package doom3; public class thefourweekworks2 { public static void main(String[] args) { // TODO Auto-generated method stub int i=0; for(i=0;i<10;i++){ if(i==5) continue; System.out.print(" "+i+" "); } } }
3. 編寫一個程序,求整數n的階乘,例如5的階乘是1*2*3*4*5(知識點:循環語句)code
package doom3; import java.util.Scanner; public class thefourweekworks3 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.print("請輸入一個數字:"); int n = input.nextInt(); int i = 1; int sum = 1; for (i = 1; i <= n; i++) { sum *= i; } System.out.println(sum); } }
4. 編寫一個程序,輸入任意學生成績,若是輸入不合法(<0或者>100),提示輸入錯誤,從新輸入,直到輸入合法程序結束(知識點:循環語句)blog
package doom3; import java.util.Scanner; public class thefourweekworks4 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.print("請輸入一名學生的成績:"); int i = input.nextInt(); while (i < 0 || i > 100) { System.out.print("你輸入的成績有問題,請從新輸入:"); i = input.nextInt(); } System.out.print("你輸入的同窗成績爲:" + i); } }
5. 假設某員工今年的年薪是30000元,年薪的年增加率6%。編寫一個Java應用程序計算該員工10年後的年薪,並統計將來10年(從今年算起)總收入。(知識點:循環語句)input
package doom3; public class thefourweekworks5 { public static void main(String[] args) { // TODO Auto-generated method stub int i = 0; double n = 30000; double count = n; for (i = 0; i <= 9; i++) { n = n * 1.06; count = count + n; } System.out.println("該員工10年後的年薪:" + n); System.out.println("該員工10年內的總收入:" + count); } }