開篇首先推薦一款REST接口調試的利器,Chrome的擴展程序Advanced REST client,功能十分齊全!使用它來模擬訪問接口能夠獲取到詳盡的信息,藉助它排查接口是否可用。 python
問題1:curl訪問API成功,可是使用python的urllib2模塊訪問卻返回400。
接口規則以下:
POST /v2.0/tokens HTTP/1.0
Host: 192.168.85.183:35357
Content-Type: application/json
Accept: application/json
{
"auth":{
"passwordCredentials":{
"username":"alan",
"password":"admin"
},
"tenantName":"swifttenant1"
}
} shell
cURL模擬訪問實現以下:
json
curl -s -d '{"auth":{"passwordCredentials":{"username":"alan","password":"admin"},"tenantName":"swifttenant1"}}' -H "Content-type: application/json" http://192.168.85.183:35357/v2.0/tokens | python -mjson.tool後臺日誌:
#!/usr/bin/python import urllib import urllib2 def curl_keystone_failed(): url = 'http://192.168.85.183:35357/v2.0/tokens' values = {"auth":{"passwordCredentials":{"username":"alan","password":"admin"},"tenantName":"swifttenant1"}} # 這裏千萬不要仿照網上的方法進行加密,由於它自己就沒有加密的一個過程!否則仍是會返回400的! # params = urllib.urlencode(values) params = str(values) headers = {"Content-type":"application/json","Accept": "application/json"} req = urllib2.Request(url, params, headers) response = urllib2.urlopen(req) print response.read() if __name__ == "__main__": curl_keystone_failed()後臺日誌:
隨後使用httplib重寫方法,查看返回的報錯信息可發現,它沒有獲取到一個有效json格式的內容,原來python傳輸的時候是嚴格斷定內容的type的。使用json來dumps一下能夠解決問題! swift
def curl_keystone(): url = 'http://192.168.85.183:35357/v2.0/tokens' values = {"auth":{"passwordCredentials":{"username":"alan","password":"admin"},"tenantName":"swifttenant1"}} params = json.dumps(values) headers = {"Content-type":"application/json","Accept": "application/json"} req = urllib2.Request(url, params, headers) response = urllib2.urlopen(req) print response.read()
後臺日誌:
2013-09-03 05:50:52.884 23199 INFO access [-] 192.168.85.185 - - [03/Sep/2013:12:50:52 +0000] "POST http://192.168.85.183:35357/v2.0/tokens HTTP/1.0" 200 2711 app