/** 題目:hdu2896 病毒侵襲 連接:http://acm.hdu.edu.cn/showproblem.php?pid=2896 題意:N(N <= 500)個長度不大於200的模式串(保證全部的模式串都不相同), M(M <= 1000)個長度不大於10000的待匹配串,問待匹配串中有哪幾個模式串, 題目保證每一個待匹配串中最多有三個模式串。 思路:ac自動機作法,字符爲可見字符,那麼直接就是他們的ascii值做爲每個字符的標誌。最多128; 因爲不超過三個,因此找到3個就能夠return ;節約時間。 AC自動機好文章:http://www.cppblog.com/menjitianya/archive/2014/07/10/207604.html */ #include<bits/stdc++.h> using namespace std; #define P pair<int,int> #define ms(x,y) memset(x,y,sizeof x) #define LL long long const int maxn = 22; const int mod = 1e9+7; const int maxnode = 500*200+10; const int sigma_size = 128; vector<int> ans; struct AhoCorasickAutomata { int ch[maxnode][sigma_size]; int val[maxnode]; int sz; int f[maxnode]; int last[maxnode]; void clear(){sz = 1; memset(ch[0],0,sizeof ch[0]); } int idx(char c){return c-'a'; } void insert(char *s,int x) { int u = 0, n = strlen(s); for(int i = 0; i < n; i++){ //int c = idx(s[i]); int c = s[i]; if(!ch[u][c]){ memset(ch[sz], 0, sizeof ch[sz]); val[sz] = 0; ch[u][c] = sz++; } u = ch[u][c]; } val[u] = x; } void find(char *T){ int n = strlen(T); int j = 0; for(int i = 0; i < n; i++){ int c = T[i]; //while(j&&!ch[j][c]) j = f[j]; j = ch[j][c]; if(val[j]) print(j); else if(last[j]) print(last[j]); if(ans.size()==3) return ; } } void print(int j) { if(j){ ans.push_back(val[j]); if(ans.size()==3) return ; print(last[j]); } } void getFail(){ queue<int> q; f[0] = 0; for(int c = 0; c < sigma_size; c++){ int u = ch[0][c]; if(u){f[u] = 0; q.push(u); last[u] = 0;} } while(!q.empty()){ int r = q.front(); q.pop(); for(int c = 0; c < sigma_size; c++){ int u = ch[r][c]; if(!u){ ch[r][c] = ch[f[r]][c]; continue; }//if(!u) continue; q.push(u); int v = f[r]; while(v&&!ch[v][c]) v = f[v]; f[u] = ch[v][c]; last[u] = val[f[u]] ? f[u] : last[f[u]]; } } } } ac ; char s[10005]; int main() { int n, m; while(scanf("%d",&n)==1) { ac.clear(); for(int i = 1; i <= n; i++){ scanf("%s",s); ac.insert(s,i); } ac.getFail(); scanf("%d",&m); int cnt = 0; for(int i= 1; i <= m; i++){ ans.clear(); scanf("%s",s); ac.find(s); if(ans.size()!=0){ cnt++; printf("web %d:",i); sort(ans.begin(),ans.end()); for(int j = 0; j < (int)ans.size(); j++){ printf(" %d",ans[j]); } printf("\n"); } } printf("total: %d\n",cnt); } return 0; } /* 3 aaa bbb ccc 2 aaabbbccc bbaacc */