SDRAM反彙編文件

本文主要介紹一個簡單的使用SDRAM器件時,地址之間的映射關係以及啓動代碼的關係linux

首先,看一個彙編文件,是啓動代碼。sass

@*************************************************************************
@ File:head.S
@ 功能:設置SDRAM,將程序複製到SDRAM,而後跳到SDRAM繼續執行
@*************************************************************************       

.equ        MEM_CTL_BASE,       0x48000000
.equ        SDRAM_BASE,         0x30000000

.text
.global _start
_start:
    bl  disable_watch_dog               @ 關閉WATCHDOG,不然CPU會不斷重啓
    bl  memsetup                        @ 設置存儲控制器
    bl  copy_steppingstone_to_sdram     @ 複製代碼到SDRAM中
    ldr pc, =on_sdram                   @ 跳到SDRAM中繼續執行
on_sdram:
    ldr sp, =0x34000000                 @ 設置堆棧
    bl  main
halt_loop:
    b   halt_loop

disable_watch_dog:
    @ 往WATCHDOG寄存器寫0便可
    mov r1,     #0x53000000
    mov r2,     #0x0
    str r2,     [r1]
    mov pc,     lr      @ 返回

copy_steppingstone_to_sdram:
    @ 將Steppingstone的4K數據所有複製到SDRAM中去
    @ Steppingstone起始地址爲0x00000000,SDRAM中起始地址爲0x30000000
    
    mov r1, #0
    ldr r2, =SDRAM_BASE
    mov r3, #4*1024
1:  
    ldr r4, [r1],#4     @ 從Steppingstone讀取4字節的數據,並讓源地址加4
    str r4, [r2],#4     @ 將此4字節的數據複製到SDRAM中,並讓目地地址加4
    cmp r1, r3          @ 判斷是否完成:源地址等於Steppingstone的未地址?
    bne 1b              @ 若沒有複製完,繼續
    mov pc,     lr      @ 返回

memsetup:
    @ 設置存儲控制器以便使用SDRAM等外設

    mov r1,     #MEM_CTL_BASE       @ 存儲控制器的13個寄存器的開始地址
    adrl    r2, mem_cfg_val         @ 這13個值的起始存儲地址
    add r3,     r1, #52             @ 13*4 = 54
1:  
    ldr r4,     [r2], #4            @ 讀取設置值,並讓r2加4
    str r4,     [r1], #4            @ 將此值寫入寄存器,並讓r1加4
    cmp r1,     r3                  @ 判斷是否設置完全部13個寄存器
    bne 1b                          @ 若沒有寫成,繼續
    mov pc,     lr                  @ 返回


.align 4
mem_cfg_val:
    @ 存儲控制器13個寄存器的設置值
    .long   0x22011110      @ BWSCON
    .long   0x00000700      @ BANKCON0
    .long   0x00000700      @ BANKCON1
    .long   0x00000700      @ BANKCON2
    .long   0x00000700      @ BANKCON3  
    .long   0x00000700      @ BANKCON4
    .long   0x00000700      @ BANKCON5
    .long   0x00018005      @ BANKCON6
    .long   0x00018005      @ BANKCON7
    .long   0x008C07A3      @ REFRESH
    .long   0x000000B1      @ BANKSIZE
    .long   0x00000030      @ MRSRB6
    .long   0x00000030      @ MRSRB7

 以及一個Makefileoop

sdram.bin : head.S leds.c arm-linux-gcc  -c -o head.o head.S arm-linux-gcc -c -o leds.o leds.c arm-linux-ld -Ttext 0x30000000 head.o leds.o -o sdram_elf arm-linux-objcopy -O binary -S sdram_elf sdram.bin arm-linux-objdump -D -m arm  sdram_elf > sdram.dis clean: rm -f   sdram.dis sdram.bin sdram_elf *.o

還有它的反彙編文件spa

sdram_elf:     file format elf32-littlearm Disassembly of section .text: 30000000 <_start>: 30000000:    eb000005     bl    3000001c <disable_watch_dog>
30000004:    eb000010     bl    3000004c <memsetup>
30000008:    eb000007     bl    3000002c <copy_steppingstone_to_sdram> 3000000c: e59ff090 ldr pc, [pc, #144]    ; 300000a4 <mem_cfg_val+0x34>

30000010 <on_sdram>: 30000010:    e3a0d30d     mov    sp, #872415232    ; 0x34000000
30000014:    eb000033     bl    300000e8 <main>

30000018 <halt_loop>: 30000018:    eafffffe     b    30000018 <halt_loop> 3000001c <disable_watch_dog>: 3000001c: e3a01453 mov r1, #1392508928    ; 0x53000000
30000020:    e3a02000     mov    r2, #0
30000024: e5812000 str r2, [r1] 30000028: e1a0f00e mov pc, lr 3000002c <copy_steppingstone_to_sdram>: 3000002c: e3a01000 mov r1, #0
30000030:    e3a02203     mov    r2, #805306368    ; 0x30000000
30000034:    e3a03a01     mov    r3, #4096    ; 0x1000
30000038:    e4914004     ldr    r4, [r1], #4 3000003c: e4824004 str r4, [r2], #4
30000040: e1510003 cmp r1, r3 30000044:    1afffffb     bne    30000038 <copy_steppingstone_to_sdram+0xc>
30000048: e1a0f00e mov pc, lr 3000004c <memsetup>: 3000004c: e3a01312 mov r1, #1207959552    ; 0x48000000
30000050:    e28f2018     add    r2, pc, #24
30000054: e1a00000 nop ; (mov r0, r0) 30000058:    e2813034     add    r3, r1, #52    ; 0x34 3000005c: e4924004 ldr r4, [r2], #4
30000060:    e4814004     str    r4, [r1], #4
30000064: e1510003 cmp r1, r3 30000068:    1afffffb     bne    3000005c <memsetup+0x10> 3000006c: e1a0f00e mov pc, lr 30000070 <mem_cfg_val>: 30000070:    22011110     andcs    r1, r1, #4
30000074:    00000700     andeq    r0, r0, r0, lsl #14
30000078:    00000700     andeq    r0, r0, r0, lsl #14 3000007c: 00000700     andeq    r0, r0, r0, lsl #14
30000080:    00000700     andeq    r0, r0, r0, lsl #14
30000084:    00000700     andeq    r0, r0, r0, lsl #14
30000088:    00000700     andeq    r0, r0, r0, lsl #14 3000008c: 00018005 andeq r8, r1, r5 30000090:    00018005 andeq r8, r1, r5 30000094:    008c07a3     addeq    r0, ip, r3, lsr #15
30000098:    000000b1     strheq    r0, [r0], -r1 3000009c: 00000030 andeq r0, r0, r0, lsr r0 300000a0: 00000030 andeq r0, r0, r0, lsr r0 300000a4: 30000010 andcc r0, r0, r0, lsl r0 300000a8: e1a00000 nop ; (mov r0, r0) 300000ac: e1a00000 nop ; (mov r0, r0) 300000b0 <wait>: 300000b0: e52db004 push {fp} ; (str fp, [sp, #-4]!) 300000b4: e28db000 add fp, sp, #0 300000b8: e24dd00c sub sp, sp, #12 300000bc: e50b0008 str r0, [fp, #-8] 300000c0: ea000002 b 300000d0 <wait+0x20> 300000c4: e51b3008 ldr r3, [fp, #-8] 300000c8: e2433001 sub r3, r3, #1 300000cc: e50b3008 str r3, [fp, #-8] 300000d0: e51b3008 ldr r3, [fp, #-8] 300000d4: e3530000 cmp r3, #0 300000d8: 1afffff9 bne 300000c4 <wait+0x14> 300000dc: e28bd000 add sp, fp, #0 300000e0: e8bd0800 pop {fp} 300000e4: e12fff1e bx lr 300000e8 <main>: 300000e8: e92d4800 push {fp, lr} 300000ec: e28db004 add fp, sp, #4 300000f0: e24dd008 sub sp, sp, #8 300000f4: e3a03000 mov r3, #0 300000f8: e50b3008 str r3, [fp, #-8] 300000fc: e59f304c ldr r3, [pc, #76]    ; 30000150 <main+0x68>
30000100:    e3a02c15     mov    r2, #5376    ; 0x1500
30000104: e5832000 str r2, [r3] 30000108:    ea000000     b    30000110 <main+0x28> 3000010c: e1a00000 nop ; (mov r0, r0) 30000110:    e59f003c     ldr    r0, [pc, #60]    ; 30000154 <main+0x6c>
30000114:    ebffffe5     bl    300000b0 <wait>
30000118:    e59f3038     ldr    r3, [pc, #56]    ; 30000158 <main+0x70> 3000011c: e51b2008 ldr r2, [fp, #-8] 30000120:    e1a02202     lsl    r2, r2, #4
30000124: e1e02002 mvn r2, r2 30000128: e5832000 str r2, [r3] 3000012c: e51b3008 ldr r3, [fp, #-8] 30000130:    e2833001     add    r3, r3, #1
30000134:    e50b3008     str    r3, [fp, #-8] 30000138:    e51b3008     ldr    r3, [fp, #-8] 3000013c: e3530008 cmp r3, #8
30000140:    1afffff1     bne    3000010c <main+0x24>
30000144:    e3a03000     mov    r3, #0
30000148:    e50b3008     str    r3, [fp, #-8] 3000014c: eaffffef b 30000110 <main+0x28>
30000150:    56000050     undefined instruction 0x56000050
30000154:    00007530 andeq r7, r0, r0, lsr r5 30000158:    56000054     undefined instruction 0x56000054 Disassembly of section .ARM.attributes: 00000000 <.ARM.attributes>: 0:    00002541     andeq    r2, r0, r1, asr #10
   4:    61656100     cmnvs    r5, r0, lsl #2
   8:    01006962     tsteq    r0, r2, ror #18 c: 0000001b andeq r0, r0, fp, lsl r0 10:    00543405     subseq    r3, r4, r5, lsl #8
  14:    01080206     tsteq    r8, r6, lsl #4
  18:    04120109     ldreq    r0, [r2], #-265    ; 0x109 1c: 01150114 tsteq r5, r4, lsl r1 20:    01180317 tsteq r8, r7, lsl r3 24:    Address 0x00000024 is out of bounds. Disassembly of section .comment: 00000000 <.comment>: 0:    3a434347     bcc    10d0d24 <SDRAM_BASE-0x2ef2f2dc>
   4:    74632820     strbtvc    r2, [r3], #-2080    ; 0x820
   8:    312d676e     teqcc    sp, lr, ror #14 c: 312e362e teqcc lr, lr, lsr #12
  10:    2e342029     cdpcs    0, 3, cr2, cr4, cr9, {1} 14:    00332e34     eorseq    r2, r3, r4, lsr lr

反彙編文件中,最左邊的數字,表示的是應該位於哪一個地址。中間是對應指令的機器碼。右邊則是彙編指令。code

 

1 爲何反彙編文件中「應該運行」地址都是3打頭的呢?orm

由於這是與連接腳本也就是makefile中的 -Ttext有關係blog

 

2 整個程序運行的順序應該是這樣的: 首先CPU自動從外接的nandflash中的前4K數據複製到SRAM中(假設從nandflash啓動)。而後CPU跳轉到SRAM中0地址運行。這一段代碼完成的工做包括了關看門狗、時鐘、初始化SDRAM、拷貝代碼從SRAM到SDRAM(實際上不少時候是從NandFlash拷貝到SDRAM),最後跳轉到SDRAM中執行。ip

 

3 何時跳到SDRAM中執行,怎麼肯定跳轉的地址博客

彙編代碼中是以下圖所示flash

 

而對應的反彙編代碼是

 

其中的「ldr pc,  [pc, #144]」

這裏是將當前的PC值加144(十進制)。

而此時PC的值是多少呢,固然是0x00000014 + 8

(1)       爲何是0x00000014不是0x30000014呢,由於此時還在SRAM中運行而非SDRAM,雖然連接地址指定該條語句應該位於0x30000014可是真正運行的地址並非由此連接而肯定。

(2)       爲何 是加8

這裏能夠參考ARM指令系統的介紹,正常模式下是+8

因此這條語句是將0x14+8+144=0xA4,而0x000000A4的內容以下圖

 

能夠看到是30000010,換而言之,此時PC值 等於了0X3000010位於SDRAM中,那此地址上的內容是什麼呢,別忘了,咱們剛把些代碼複製到了SDRAM中。此時的代碼如上上圖所示。

就此,恢復正常工做,此時程序所謂的「應該運行地址」纔等於了「實際運行地址」

 

關於連接地址問題,可參見另一篇相關的博客。

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