Linux shell腳本007（select菜單選項）

#!/bin/bash names=( "張三" "李四" "王二" ) echo "Please guess who is my friend :" select var in ${names[@]} do if [ x$var = x"李四" ]; then #這裏$var和"李四"前邊的x，，是爲了不，當輸入的選擇不在s

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