題目大意:判斷兩個字符串是否具備相同的結構code
思路:構造一個map,存儲每一個字符的差,遍歷字符串,判斷兩個兩個字符串中相同位置字符的差是否相同ip
Java實現:leetcode
public boolean isIsomorphic(String s, String t) { Map<String, Integer> map = new HashMap<>(); for (int i=0; i<s.length(); i++) { char c1 = s.charAt(i); char c2 = t.charAt(i); String key1 = "s_" + c1; String key2 = "t_" + c2; if (map.get(key1) == null) { map.put(key1, c1 - c2); } else if (map.get(key1) != c1 - c2) { return false; } if (map.get(key2) == null) { map.put(key2, c2 - c1); } else if (map.get(key2) != c2 - c1) { return false; } } return true; }
別人的實現:字符串
public boolean isIsomorphic(String s1, String s2) { int[] m = new int[512]; for (int i = 0; i < s1.length(); i++) { if (m[s1.charAt(i)] != m[s2.charAt(i)+256]) return false; m[s1.charAt(i)] = m[s2.charAt(i)+256] = i+1; } return true; }