MYSQL命令行輸入密碼警告問題"mysql: [Warning]"解決

1.1 問題顯示

[root@localhost ~]# mysql -uroot -p1234567
mysql: [Warning] Using a password on the command line interface can be insecure.

1.2 解決方法

1.2.1 方法一

一、將密碼寫入到主配置文件中

[root@localhost ~]# vim /etc/my.cnf
[mysqldump]
user=root
password=1234567

[mysql]
user=root
password=1234567

二、直接使用命令登陸，再也無需輸入帳號密碼

[root@localhost ~]# mysql
Welcome to the MySQL monitor.  Commands end with ; or \g.
Your MySQL connection id is 10
Server version: 5.7.18-log Source distribution
Copyright (c) 2000, 2017, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.
mysql>

1.2.2 方法二

一、自動配置MYSQL密文密碼

該操做會在用戶家目錄下生成一個隱藏文件".mylogin.cnf"，裏面記錄了MYSQL的密文的密碼，只要配置了之後，咱們也是直接使用命令登陸，再也無需輸入帳號密碼了，若是你想取消，刪除此文件便可。

[root@localhost ~]# mysql_config_editor set --user=root --host=localhost --port=3306 --password
Enter password: 輸入密碼

二、直接使用命令登陸，再也無需輸入帳號密碼

[root@localhost ~]# mysql
Welcome to the MySQL monitor.  Commands end with ; or \g.
Your MySQL connection id is 11
Server version: 5.7.18-log Source distribution
Copyright (c) 2000, 2017, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.
mysql>

1.2.3 方法三

一、直接使用命令登陸，屏蔽錯誤信息

因爲告警信息是標準錯誤，咱們能夠將標準錯誤的輸出信息輸出爲空。

[root@localhost ~]# mysql -uroot -p1234567 2>/dev/null
Welcome to the MySQL monitor.  Commands end with ; or \g.
Your MySQL connection id is 36
Server version: 5.7.18-log Source distribution
Copyright (c) 2000, 2017, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.
mysql>