Given a binary array, find the maximum number of consecutive 1s in this array.git
Example 1:數組
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:this
0
and 1
.題意是在一個二進制數組中,找到此數組中連續1的最大數。spa
這個循環一遍記錄最大連續值便可,C++實現以下:code
int findMaxConsecutiveOnes(vector<int>& nums) { int count=0; int max=0; for(int i=0;i<nums.size();i++) { if(nums[i]==1) { count++; } else { count=0; } if(count>max) max=count; } return max; }