兩兩配對差值最小 拼多多[編程題](python AC解)

n = int(input()) l = [int(val) for val in input().split(' ')] l = sorted(l) mina = None maxa = None for i in range(n//2): tempres = l[i] + l[-(i+1)] mina = tempres if mina == None else min(min

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