mongodb 語句和SQL語句對應（SQL to Aggregation Mapping Chart）

SQL to Aggregation Mapping Chart

https://docs.mongodb.com/manual/reference/sql-aggregation-comparison/

On this page

• Examples
• Additional Resources

The aggregation pipeline allows MongoDB to provide native aggregation capabilities that corresponds to many common data aggregation operations in SQL.

The following table provides an overview of common SQL aggregation terms, functions, and concepts and the corresponding MongoDB aggregation operators:

SQL Terms, Functions, and Concepts	MongoDB Aggregation Operators
WHERE	$match
GROUP BY	$group
HAVING	$match
SELECT	$project
ORDER BY	$sort
LIMIT	$limit
SUM()	$sum
COUNT()	$sum
join	$lookup New in version 3.2.

Examples

The following table presents a quick reference of SQL aggregation statements and the corresponding MongoDB statements. The examples in the table assume the following conditions:

• The SQL examples assume two tables, orders and order_lineitem that join by theorder_lineitem.order_id and the orders.id columns.

• The MongoDB examples assume one collection orders that contain documents of the following prototype:

  {
    cust_id: "abc123", ord_date: ISODate("2012-11-02T17:04:11.102Z"), status: 'A', price: 50, items: [ { sku: "xxx", qty: 25, price: 1 }, { sku: "yyy", qty: 25, price: 1 } ] } 

SQL Example	MongoDB Example	Description
SELECT COUNT(*) AS count FROM orders	db.orders.aggregate( [ { $group: { _id: null, count: { $sum: 1 } } } ] )	Count all records from orders
SELECT SUM(price) AS total FROM orders	db.orders.aggregate( [ { $group: { _id: null, total: { $sum: "$price" } } } ] )	Sum the price field from orders
SELECT cust_id, SUM(price) AS total FROM orders GROUP BY cust_id	db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } } ] )	For each unique cust_id, sum theprice field.
SELECT cust_id, SUM(price) AS total FROM orders GROUP BY cust_id ORDER BY total	db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $sort: { total: 1 } } ] )	For each unique cust_id, sum theprice field, results sorted by sum.
SELECT cust_id, ord_date, SUM(price) AS total FROM orders GROUP BY cust_id, ord_date	db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { month: { $month: "$ord_date" }, day: { $dayOfMonth: "$ord_date" }, year: { $year: "$ord_date"} } }, total: { $sum: "$price" } } } ] )	For each unique cust_id, ord_dategrouping, sum the price field. Excludes the time portion of the date.
SELECT cust_id, count(*) FROM orders GROUP BY cust_id HAVING count(*) > 1	db.orders.aggregate( [ { $group: { _id: "$cust_id", count: { $sum: 1 } } }, { $match: { count: { $gt: 1 } } } ] )	For cust_id with multiple records, return the cust_id and the corresponding record count.
SELECT cust_id, ord_date, SUM(price) AS total FROM orders GROUP BY cust_id, ord_date HAVING total > 250	db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { month: { $month: "$ord_date" }, day: { $dayOfMonth: "$ord_date" }, year: { $year: "$ord_date"} } }, total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } } ] )	For each unique cust_id, ord_dategrouping, sum the price field and return only where the sum is greater than 250. Excludes the time portion of the date.
SELECT cust_id, SUM(price) as total FROM orders WHERE status = 'A' GROUP BY cust_id	db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } } ] )	For each unique cust_id with status A, sum the price field.
SELECT cust_id, SUM(price) as total FROM orders WHERE status = 'A' GROUP BY cust_id HAVING total > 250	db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } } ] )	For each unique cust_id with status A, sum the price field and return only where the sum is greater than 250.
SELECT cust_id, SUM(li.qty) as qty FROM orders o, order_lineitem li WHERE li.order_id = o.id GROUP BY cust_id	db.orders.aggregate( [ { $unwind: "$items" }, { $group: { _id: "$cust_id", qty: { $sum: "$items.qty" } } } ] )	For each unique cust_id, sum the corresponding line item qty fields associated with the orders.
SELECT COUNT(*) FROM (SELECT cust_id, ord_date FROM orders GROUP BY cust_id, ord_date) as DerivedTable	db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { month: { $month: "$ord_date" }, day: { $dayOfMonth: "$ord_date" }, year: { $year: "$ord_date"} } } } }, { $group: { _id: null, count: { $sum: 1 } } } ] )	Count the number of distinctcust_id, ord_date groupings. Excludes the time portion of the d