133. Clone Graph

Given a reference of a node in a connected undirected graph, return a deep copy (clone) of the graph. Each node in the graph contains a val (int) and a list (List[Node]) of its neighbors.

 

Example:

Input:
{"$id":"1","neighbors":[{"$id":"2","neighbors":[{"$ref":"1"},{"$id":"3","neighbors":[{"$ref":"2"},{"$id":"4","neighbors":[{"$ref":"3"},{"$ref":"1"}],"val":4}],"val":3}],"val":2},{"$ref":"4"}],"val":1}

Explanation:
Node 1's value is 1, and it has two neighbors: Node 2 and 4.
Node 2's value is 2, and it has two neighbors: Node 1 and 3.
Node 3's value is 3, and it has two neighbors: Node 2 and 4.
Node 4's value is 4, and it has two neighbors: Node 1 and 3.

 

Note:

1. The number of nodes will be between 1 and 100.
2. The undirected graph is a simple graph, which means no repeated edges and no self-loops in the graph.
3. Since the graph is undirected, if node p has node q as neighbor, then node q must have node p as neighbor too.
4. You must return the copy of the given node as a reference to the cloned graph.

 

Approach #1: DFS. [Java]

/*
// Definition for a Node.
class Node {
    public int val;
    public List<Node> neighbors;

    public Node() {}

    public Node(int _val,List<Node> _neighbors) {
        val = _val;
        neighbors = _neighbors;
    }
};
*/
class Solution {
    public Node clone(Node node, HashMap<Integer, Node> map) {
        if (node == null) return null;
        if (map.containsKey(node.val))
            return map.get(node.val);
        Node newNode = new Node(node.val, new ArrayList<Node>());
        map.put(newNode.val, newNode);
        for (Node neighbor : node.neighbors)
            newNode.neighbors.add(clone(neighbor, map));
        return newNode;
    }
    
    public Node cloneGraph(Node node) {
        HashMap<Integer, Node> map = new HashMap<>();
        return clone(node, map);
    }
}

　　

Analysis:

https://leetcode.com/problems/clone-graph/discuss/42309/Depth-First-Simple-Java-Solution