python變量運算符分支結構循環結構及例題

第一週總結複習
python的[官方網站](http://python.org)
##變量
'''
1.變量的做用:變量是數據的載體

2.變量的命名:字母數字下劃線開頭,不能用數字開頭
            不能用關鍵字,特殊符號 $等開頭
大小寫敏感(a 和 A 不同)
PEP 8 要求:
用小寫字母拼寫,多個單詞用下劃線隔開
受保護的實例屬性用單個下劃線開頭
私有的實例屬性用兩個下劃線開頭
3.變量的類型: int(),float(),str(), chr(), ord()--將字符串轉化成對應的編碼

'''
##運算符
'''
1.賦值運算符: =(賦值)、+=(加賦值)、-=(減賦值)、*=(乘賦值)、/=(除賦值)、%=(取餘賦值)
2.算數運算符: +、-、*、/、%
3.關係運算符: ==(等於)、!=(不等於)、>(大於)、<(小於)、>=(大於等於)、<=(小於等於)
4.邏輯運算符:and(與)、or(或)、not(非)
5.身份運算符
'''
##分支結構
'''
'''
##循環結構
'''
1.while循環:只要某一條件成立,就不斷執行循環體裏的代碼,直到該條件再也不成立,條件是否成立一樣是邏輯值來表示
2.for循環:循環的循環次數通常是事先定好的,將一個條件變量從某個豈是值開始,一直爹逮到某個終止值後結束
循環控制--pass:什麼也不作,只是佔據一行代碼的位置;
continue:表示當即退出本輪循環,不運行本輪循環的後續代碼,並繼續執行接下來的循環;
break: 表示當即退出整個循環,後續循環再也不執行
'''
python例題練習:(全部代碼在python3.5環境下可運行)
1.輸入三個數字,計算三角形面積周長:
import math
a = float(input("請輸入三角形邊第一條邊長:"))
b = float(input("請輸入三角形邊第二條邊長:"))
c = float(input("請輸入三角形邊第三條邊長:"))
while True:
    if a + b > c and a + c > b and b + c > a:
          perimeter = a + b + c
          p = perimeter / 2
          g = math.sqrt(p * (p - a) * (p - b) * (p - c))
          print("三角形周長爲:%.2f" % perimeter)
          print("三角形面積爲: %.2f" % g)
    else:
        print("-------------This is not triangle!!----------------")
    break

 


2.用戶輸入數字,由電腦來猜:
from random import randint

user_input = int(input("please input the number you want computer guess>>>:"))
counter = 0
low = 1
high = 100
money = 1000
while True:
    guess = randint(low, high)
    print(guess)
    counter += 1
    if user_input == guess:
        print("congratulation, computer guess right")
        print("total guess:", counter)
        money += 200
        print("computer has: ",money)
        if money < 500:
           print(" computer you are fucking stupid!!!!")
        quit()
    elif user_input > guess:
        low = guess + 1
        print("computer guess a higher number")
        money -= 100
    else:  # user_input < guess
        high = guess - 1
        print("computer guess a lower number:")
        money -= 100

3.和電腦猜石頭剪刀布:python

from random import randint while True: user_guess=int(input("1-- scisoor, 2--stone, 3--handkerchief:")) cm_guess = randint(1, 3) print(cm_guess) if user_guess == cm_guess: print("no one lose") elif user_guess == 1 and cm_guess == 2: print("user win") elif user_guess == 2 and cm_guess == 3: print("computer win") elif user_guess == 3 and cm_guess == 2: print("user win") else: #user_guess == 3 and cm_guess == 1:
        print("computer win")

4. 打印(2,100)全部素數app

import math
def get_prime(maxNum):
    primeList = []
    for x in range(2, maxNum + 1):
        a = math.sqrt(x)
        for prime in primeList:
            if prime > a:
                primeList.append(x)
                break
            if x % prime == 0:
                break
        else:
            primeList.append(x)
    return primeList

print(get_prime(100))

5. 打印 '*'dom

row = int(input("please input the number of row:>>>>>"))
for i in range(row):
    for j in range(row):
        if j < row - i - 1:
            print(' ', end = '')
        else:
            print('*', end = '')
    print()

6. 打印三角形的大寫字母,每行的字母同樣:網站

for x in range(65, 70):
        for y in range(64, x):
            print(chr(x), end = '')
        print()

7. 找出1-10000的水仙花數:ui

from time import time
from math import sqrt
start = time()
for n in range(1, 10000):
my_sum = 0
for factor in range(1,int(sqrt(n)) + 1):
if n % factor == 0:
my_sum += factor
if factor != 1 and factor != n // factor:
my_sum += n // factor
if my_sum == n:
print(n)
end = time()
print((end - start), 's')

8. 五人抓魚問題:A把魚分紅五份後扔走一條拿走本身那部分,BCDE用和A同樣方法分魚,求魚一共有多少條(本題使用窮舉法):編碼

fish = 1
while True:
    total = fish
    is_enough = True
    for _ in range(5):
        if (total - 1) % 5 == 0:
            total = (total - 1) // 5 * 4
        else:
            is_enough = False
            break
    if is_enough:
        print("the min number of fish is:", fish)
        break

    fish += 1

 9. craps 賭博遊戲spa

# craps 賭博遊from random import randintmoney = 1000while money > 0:    print('players money:', money)    while True:        debt = int(input('please debt:'))        if 0 < debt <= money:            break    face1 = randint(1, 6)    face2 = randint(1, 6)    go_on = False    first_point = face1 + face2    print('玩家搖出了%d點' %first_point)    if first_point == 7 or first_point == 11:        print(" you win!")        money += debt        print("user have: %d" % money)    elif first_point == 2 or first_point == 3 or first_point == 12:        print(" computer win!")        money -= debt        print("user have: %d" % money)    else:        go_on = True    while go_on:        face1 = randint(1, 6)        face2 = randint(1, 6)        current_point = face2 + face1        print('玩家搖出了%d點' % current_point)        if current_point == 7:            print("user lose!")            money -= debt            go_on = False            print("user have: %d" % money)        elif current_point == first_point:            print("user win!")            money += debt            go_on = False            print("user have: %d" %money)
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