給定一個天數，計算該天在某年的月、日

#include <stdio.h>

void getMonthAndDays(int year, int *month, int *day);

int main()

{

int month = 0;

int day = 63;

getMonthAndDays(2012, &month, &day);

printf("month:%2d day: %2d", month, day);

return 0;

}

void getMonthAndDays(int year, int *month, int *day)

{

if (year > 0 && (*day) > 0)

{

int y = (year%100 != 0 && year%4 == 0) || (year%400 == 0); //閏年

int days[] = {31, 28 + y, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; //初始化一個數組，記錄每月的天數 

// days[1] += (year%100 != 0 && year%4 == 0) || (year%400 == 0); //閏年，二月多一天 

for (*month = 1; *day - days[*month - 1] > 0; (*month)++) //若是day的值比下一個月的天數多，則減去，月數加1 

{

*day -= days[*month - 1];

}

}

}