hdu1716 排列2

12  21ios

123 132  213 231 321 312數組

....spa

每次都將後面n-1位進行全排列。遞歸的出口當起始座標等於終止座標時。須要還原。設計

設計標記數組。由於須要從小到大輸出。code

#define _CRT_SECURE_NO_DEPRECATE
#include<stdio.h>  
#include<string.h>  
#include<iostream>
#include<string>
#include<algorithm>
using namespace std;
int visited[10010];
int a[4];
void swap(int a[], int i, int j)
{
    int temp = a[i];
    a[i] = a[j];
    a[j] = temp;
}

void perm(int a[], int k, int m, int pk, int pm)
{
    if (k == m)
    {
        int sum = 0;
        for (int i = pk; i <= pm; i++)
        {
            sum = sum * 10 + a[i];
        }
        visited[sum] = 1;
    }
    else
    {
        for (int i = k; i <= m; i++)
        {
            swap(a, k, i);
            perm(a, k + 1, m, pk, pm);
            swap(a, k, i);
        }
    }
}

int main()
{
    int t = 0;
    while (scanf("%d", &a[0]) != EOF)
    {
        scanf("%d%d%d", &a[1], &a[2], &a[3]);
        if (a[1] == 0 && a[2] == 0 && a[0] == 0 && a[3] == 0)
            break;
        if (t != 0)
            printf("\n");
        t = 1;
        sort(a, a + 4);
        memset(visited, 0, sizeof(visited));
        perm(a, 0, 3, 0, 3);
        int k;
        int sign = 0;
        for (int i = 1000; i < 10000; i++)
        {
            if (visited[i]==1)
            {
                sign++;
                if (sign== 1)
                {
                    k = i / 1000;
                    printf("%d", i);
                }
                else
                {
                    if (i / 1000 != k)
                    {
                        printf("\n");
                        k = i / 1000;
                    }
                    else
                        printf(" ");
                    printf("%d", i);
                }
            }
        }
        printf("\n");
    }
    return 0;
}
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