解題思路:數組
1. 先將兩個數組進行合併,能夠利用C語言的memcpy函數進行;函數
2. 將新數組進行冒泡排序;排序
3. 過濾掉重複元素;element
代碼以下:input
#include <stdlib.h> #include<string.h>string
//冒泡排序it
void sortArray(int * inArr, int arrCount)io
{ function
int i = 0; sort
for (int k = 0; k < arrCount - 1; k++)
{
for (int p = 0; p < arrCount - k - 1; p++)
{
if (inArr[p] > inArr[p + 1])
{
int temp = inArr[p];
inArr[p] = inArr[p + 1];
inArr[p + 1] = temp;
}
}
}
}
/* function:merge two arrays into one new array and sort its element by asc, then filter the dunplicate elements.
input:int * pArray1 :整型數組1 int iArray1Num:數組1元素個數 int * pArray2 :整型數組2 int iArray2Num:數組2元素個數
輸出:int * pOutputArray:合併後的數組 int * iOutputNum:合併後數組元素個數
返回:void */
void CombineBySort(int * pArray1, int iArray1Num, int * pArray2, int iArray2Num, int * pOutputArray, int * iOutputNum)
{
if (pArray1 == NULL || pArray2 == NULL || pOutputArray == NULL || iOutputNum == NULL) return;
if (iArray1Num == 0 && iArray2Num == 0) return;
int * pTempArray = (int *)malloc(sizeof(int) * (iArray1Num + iArray2Num));
if (pTempArray == NULL) return;
memcpy(pTempArray, pArray1, iArray1Num * sizeof(int));
memcpy(pTempArray + iArray1Num, pArray2, iArray2Num * sizeof(int));
sortArray(pTempArray, (iArray1Num + iArray2Num));
//進行了數組剔除,而且賦值給輸出數組中
int idx = 0;
pOutputArray[0] = pTempArray[0];
for (int q = 1; q < iArray1Num + iArray2Num; q++)
{
if (pOutputArray[idx] == pTempArray[q]) continue;
idx++;
pOutputArray[idx] = pTempArray[q];
}
*iOutputNum = idx + 1;
free(pTempArray);
return;
}