[LeetCode] 22. 括號生成

題目連接:https://leetcode-cn.com/problems/generate-parentheses/

題目描述:

給出 n 表明生成括號的對數，請你寫出一個函數，使其可以生成全部可能的而且有效的括號組合。

示例:

[
  "((()))",
  "(()())",
  "(())()",
  "()(())",
  "()()()"
]

思路:

回溯算法

遞歸過程當中,經過左括號和右括號的個數判斷是否還能夠組成有效的括號的組合

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代碼:

python

class Solution:
    def generateParenthesis(self, n: int) -> List[str]:
        res = []
        
        def helper(left_p, right_p, tmp):
            if left_p == 0 and right_p == 0:
                res.append(tmp)
                return
            if left_p < 0 or right_p < 0 or left_p > right_p:
                return 
            helper(left_p-1, right_p, tmp+"(")
            helper(left_p, right_p-1, tmp+")")
        helper(n, n, "")
        return res

java

class Solution {
    public List<String> generateParenthesis(int n) {
        ArrayList<String> res = new ArrayList<String>();
        backtrack(res, "", n, n);
        return res;

    }

    public void backtrack(ArrayList<String> res, String s, int left_p, int right_p) {
        if (left_p == 0 && right_p == 0) {
            res.add(s);
            return;
        }
        if (left_p < 0 || right_p < 0 || left_p > right_p) return;
        backtrack(res,s+"(",left_p-1,right_p);
        backtrack(res,s+")",left_p,right_p-1);
    }
}