int pnpoly(int nvert, float *vertx, float *verty, float testx, float testy) //testx,testy 是要判斷的點 { int i, j, c = 0; for (i = 0, j = nvert-1; i < nvert; j = i++) //對於多邊形相鄰的兩點 { if ( ((verty[i]>testy) != (verty[j]>testy)) && //根據上圖 (testx < (vertx[j]-vertx[i]) * (testy-verty[i]) / (verty[j]-verty[i]) + vertx[i]) ) c = !c; } return c; }轉自 http://www.javashuo.com/article/p-aektebzd-bg.html