Given a string containing only 'A' - 'Z', we could encode it using the following method:
1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, '1' should be ignored.
The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only 'A' - 'Z' and the length is less than 10000.
For each test case, output the encoded string in a line.
ABC
A2B3C
題意是說假如輸入「AABBAA」 應輸入2A2B2A(坑在這)
#include<iostream>
#include<string>
#include<math.h>
#include<string.h>
#include<stdio.h>
#include<algorithm>
#include<map>
using namespace std;
int main()
{
int num,j,k,i;
cin>>num;
while(num--)
{
string s1;
int sum=0,k=0;
cin>>s1;
sum=0;
for(i=1;i<=s1.size();i++)
{
if(s1[i]!=s1[i-1])
{
sum=i-k+1-1;
if(sum==1)
cout<<s1[i-1];
else
cout<<sum<<s1[i-1];
k=i;
}
}
cout<<endl;
}
return 0;
}