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找出全部員工當前(to_date='9999-01-01')具體的薪水salary狀況,對於相同的薪水只顯示一次,並按照逆序顯示
CREATE TABLE salaries
(emp_no
int(11) NOT NULL,salary
int(11) NOT NULL,from_date
date NOT NULL,to_date
date NOT NULL,
PRIMARY KEY (emp_no
,from_date
));
spa
select distinct s.salary from salaries s where s.to_date = '9999-01-01' order by s.salary desc;
獲取全部部門當前manager的當前薪水狀況,給出dept_no, emp_no以及salary,當前表示to_date='9999-01-01'
CREATE TABLE dept_manager
(dept_no
char(4) NOT NULL,emp_no
int(11) NOT NULL,from_date
date NOT NULL,to_date
date NOT NULL,
PRIMARY KEY (emp_no
,dept_no
));
CREATE TABLE salaries
(emp_no
int(11) NOT NULL,salary
int(11) NOT NULL,from_date
date NOT NULL,to_date
date NOT NULL,
PRIMARY KEY (emp_no
,from_date
));code
此題與前面第三題相似,思路以下: 一、先用INNER JOIN鏈接兩張表,限制條件是兩張表的emp_no相同,即d.emp_no = s.emp_no,而且將salaries用別名s代替,dept_manager用別名d代替 二、根據題意,要獲取當前manager的當前salary狀況,再加上限制條件d.to_date = '9999-01-01' AND s.to_date = '9999-01-01'便可(由於同一emp_no在salaries表中對應多條漲薪記錄,而當s.to_date = '9999-01-01'時是該員工當前的薪水記錄) SELECT d.dept_no, d.emp_no, s.salary FROM salaries AS s INNER JOIN dept_manager AS d ON d.emp_no = s.emp_no AND d.to_date = '9999-01-01' AND s.to_date = '9999-01-01'
select d.dept_no,d.emp_no,s.salary from salaries s,dept_manager d where d.emp_no = s.emp_no and s.to_date = '9999-01-01' and d.to_date = '9999-01-01';
獲取全部非manager的員工emp_no
CREATE TABLE dept_manager
(dept_no
char(4) NOT NULL,emp_no
int(11) NOT NULL,from_date
date NOT NULL,to_date
date NOT NULL,
PRIMARY KEY (emp_no
,dept_no
));
CREATE TABLE employees
(emp_no
int(11) NOT NULL,birth_date
date NOT NULL,first_name
varchar(14) NOT NULL,last_name
varchar(16) NOT NULL,gender
char(1) NOT NULL,hire_date
date NOT NULL,
PRIMARY KEY (emp_no
));blog
方法一:使用NOT IN選出在employees但不在dept_manager中的emp_no記錄 SELECT emp_no FROM employees WHERE emp_no NOT IN (SELECT emp_no FROM dept_manager) 方法二:先使用LEFT JOIN鏈接兩張表,再今後表中選出dept_no值爲NULL對應的emp_no記錄 SELECT emp_no FROM (SELECT * FROM employees LEFT JOIN dept_manager ON employees.emp_no = dept_manager.emp_no) WHERE dept_no IS NULL 方法三:方法二的簡版,使用單層SELECT語句便可 SELECT employees.emp_no FROM employees LEFT JOIN dept_manager ON employees.emp_no = dept_manager.emp_no WHERE dept_no IS NULL