按照數組順序給對象從新組合成新對象

需求：按照後臺返回的數組的順序，和返回的對象的鍵值合成新的對象，便於渲染到頁面上

let obj={
        '213_tsxRaXuUEMXLEFWkp4bwKL': "2019-02-26",
        '2771_CGeEeRyBRdWWkK3ZAvGAWo': "充足",
        '5451_BMkcv5nT9XK2g6QBFjqYuH': ["測試部"],
        '6725_gNSy4ksbBGhVAhYdurThJL': "管理員",
        '7937_Sg4nvPG7qVrwrFwoBHexcj': "",
        '9166_yL68EB3pCT3DcZMD4QxR26': ''
        };//後臺返回的鍵值對對象
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//須要按照此數組順序
let obj1=["213_tsxRaXuUEMXLEFWkp4bwKL",
 "6725_gNSy4ksbBGhVAhYdurThJL", 
 "5451_BMkcv5nT9XK2g6QBFjqYuH",
 "2771_CGeEeRyBRdWWkK3ZAvGAWo" ,
 "7937_Sg4nvPG7qVrwrFwoBHexcj",
 "9166_yL68EB3pCT3DcZMD4QxR26"]
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//根據上面obj1的順序取出dname，結合obj的鍵值合成新的對象
let info={
        '213_tsxRaXuUEMXLEFWkp4bwKL': {dname: "填寫日期", field_id: "213_tsxRaXuUEMXLEFWkp4bwKL", id: "213_tsxRaXuUEMXLEFWkp4bwKL", dfield: "f5"},
        '2771_CGeEeRyBRdWWkK3ZAvGAWo': {dname: "今日完成工做", field_id: "2771_CGeEeRyBRdWWkK3ZAvGAWo", id: "2771_CGeEeRyBRdWWkK3ZAvGAWo",dfield: "f8"},
        '6725_gNSy4ksbBGhVAhYdurThJL': {dname: "填寫人", field_id: "6725_gNSy4ksbBGhVAhYdurThJL", id: "6725_gNSy4ksbBGhVAhYdurThJL",dfield: "f6"},
        '7937_Sg4nvPG7qVrwrFwoBHexcj': {dname: "未完成工做", field_id: "7937_Sg4nvPG7qVrwrFwoBHexcj", id: "7937_Sg4nvPG7qVrwrFwoBHexcj",dfield: "f9"},
        '9166_yL68EB3pCT3DcZMD4QxR26': {dname: "備註", field_id: "9166_yL68EB3pCT3DcZMD4QxR26", id: "9166_yL68EB3pCT3DcZMD4QxR26",dfield: "f10"},
        '5451_BMkcv5nT9XK2g6QBFjqYuH': {dname: "所在部門", field_id: "5451_BMkcv5nT9XK2g6QBFjqYuH", id: "5451_BMkcv5nT9XK2g6QBFjqYuH",dfield: "f7"}
        }
       ，
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解決方法：(哈哈，就是二次遍歷，可是遍歷的順序要注意，才接觸，因此不懂得能夠試試反過來遍歷，看到問題就長記性了）

 一、先遍歷obj1,由於是按照obj1的順序 

二、obj1裏遍歷obj對象 

三、判斷obj的第i個鍵名是否和obj1[j]相等 

四、在判斷裏組合本身想要的數據結構

let arr = [];
 for(let j=0;j<obj1.length;j++){
      for (let i in obj){
            let obj2={}
            console.log('是否obj1[j]==i相等',j,obj1[j]==i)
             if(obj1[j]==i){
                  obj2.name=info[i].dname;
                  obj2.value=obj[i];
                  console.log('obj2 ',obj2)
                  arr.push(obj2)
          }
     }
 }
        console.log('arr ',arr)
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