Java判斷一個時間是否在時間區間內

package com.liying.tiger.test;

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

public class Test {
public static void main(String[] args) throws ParseException {
String format = "HH:mm:ss";


//Date nowTime = new SimpleDateFormat(format).parse("09:27:00");
Date now = new Date();
DateFormat dateFormat = DateFormat.getTimeInstance();//獲取時分秒
//獲得當前時間的時分秒
String nowStr = dateFormat.format(now);

Date nowTime = new SimpDateFormat(format).parse(nowStr);

Date startTime = new SimpleDateFormat(format).parse("09:27:00");
Date endTime = new SimpleDateFormat(format).parse("09:27:59");
System.out.println(isEffectiveDate(nowTime, startTime, endTime));
}

/**
* 判斷當前時間是否在[startTime, endTime]區間，注意時間格式要一致
* 
* @param nowTime 當前時間
* @param startTime 開始時間
* @param endTime 結束時間
* @return
* @author jqlin
*/
public static boolean isEffectiveDate(Date nowTime, Date startTime, Date endTime) {
if (nowTime.getTime() == startTime.getTime()
|| nowTime.getTime() == endTime.getTime()) {
return true;
}

Calendar date = Calendar.getInstance();
date.setTime(nowTime);

Calendar begin = Calendar.getInstance();
begin.setTime(startTime);

Calendar end = Calendar.getInstance();
end.setTime(endTime);

if (date.after(begin) && date.before(end)) {
return true;
} else {
return false;
}
}
}

轉載至：https://www.cnblogs.com/linjiqin/p/8119338.html