The Employee
table holds all employees. Every employee has an Id, and there is also a column for the department Id.ui
+----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000 | 1 | | 2 | Henry | 80000 | 2 | | 3 | Sam | 60000 | 2 | | 4 | Max | 90000 | 1 | | 5 | Janet | 69000 | 1 | | 6 | Randy | 85000 | 1 | +----+-------+--------+--------------+
The Department
table holds all departments of the company.spa
+----+----------+ | Id | Name | +----+----------+ | 1 | IT | | 2 | Sales | +----+----------+
Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.code
+------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Max | 90000 | | IT | Randy | 85000 | | IT | Joe | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 | +------------+----------+--------+
select d.Name Department, e1.Name Employee, e1.Salary from Employee e1 join Department d on e1.DepartmentId = d.Id where 3 > (select count(distinct(e2.Salary)) from Employee e2 where e2.Salary > e1.Salary and e1.DepartmentId = e2.DepartmentId );