ACL

access匹配原則:從前匹配ui

Branch#sh run int e0/0.1
Building configuration...

Current configuration : 116 bytes
!
interface Ethernet0/0.1
 encapsulation dot1Q 10
 ip address 10.1.100.254 255.255.255.0
 ip access-group 1 in     #在接口上應用
end

Branch#sh run | s acce
 ip access-group 1 in
access-list 1 deny   10.1.100.2
access-list 1 permit any
PC1>ping 10.1.200.2
Type escape sequence to abort.
Sending 5, 100-byte ICMP Echos to 10.1.200.2, timeout is 2 seconds:
U.U.U

 


此時查看access-list會發現有配到的數據
Branch#sh ip acce 
Standard IP access list 1
10 deny 10.1.100.2 (26 matches)
20 permit any

接下改變PC1的IP
PC1#sh run int e0/1
Building configuration...

Current configuration : 66 bytes
!
interface Ethernet0/1
 ip address 10.1.100.2 255.255.255.0
end

PC1#conf t
Enter configuration commands, one per line.  End with CNTL/Z.
PC1(config)#int e0/1
PC1(config-if)#ip add 10.1.100.1 255.255.255.0
PC1(config-if)#end  
PC1#ping 10.1.200.2  
Type escape sequence to abort.
Sending 5, 100-byte ICMP Echos to 10.1.200.2, timeout is 2 seconds:
!!!!!
Success rate is 100 percent (5/5), round-trip min/avg/max = 1/2/3 ms
Branch#sh ip acce
Standard IP access list 1
    10 deny   10.1.100.2 (14 matches)
    20 permit any (5 matches)

 

思考:此時如果想在這個網段中放行奇數IP拒絕偶數IP,須要怎麼作呢?spa

答:只須要這樣作就好

Branch(config)#access-list 1 permit 10.1.100.3 0.0.0.254 (只需加上掩碼)
Branch(config)#do sh ip acces
Standard IP access list 1
10 permit 10.1.100.1, wildcard bits 0.0.0.254code

標準的ACL功能有限,在匹配流量的時候,僅僅可以匹配IP頭部的源IP地址blog

host 參數表明通配符掩碼爲 32 bit嚴格匹配接口

any 參數表明匹配全部ip

 
PC1#conf t Enter configuration commands, one per line. End with CNTL
/Z. PC1(config)#int e0/1 PC1(config-if)#ip add 10.1.100.4 255.255.255.0 PC1(config-if)#do ping 10.1.200.2 Type escape sequence to abort. Sending 5, 100-byte ICMP Echos to 10.1.200.2, timeout is 2 seconds: U.U.U Success rate is 0 percent (0/5) PC1(config-if)#ip add 10.1.100.3 255.255.255.0 PC1(config-if)#do ping 10.1.200.2 Type escape sequence to abort. Sending 5, 100-byte ICMP Echos to 10.1.200.2, timeout is 2 seconds: !!!!! Success rate is 100 percent (5/5), round-trip min/avg/max = 1/1/3 ms
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