使用C#實現一個二叉樹及其基本操做, 配合xunit來作單元測試; 因此數據結構的定義和算法均使用C#實現;node
二叉樹或爲空樹, 或是由一個根結點加上兩棵分別稱爲左子樹和右子樹的、互不交的二叉樹組成;算法
二叉樹遍歷的遞歸算法比較簡潔, 思路比較清晰, 可是非遞歸的版本, 我的以爲有點難度, 我最開始看的北大一個課程中的二叉樹的非遞歸算法, 思路很巧妙, 可是不是那麼容易想到的, 後來我本身思考了一段時間, 實現了我本身版本的非遞歸遍歷算法;數據結構
這裏我用xunit作的單元測試來驗證算法, 測試代碼可能不是很規範...app
數據結構的定義:性能
public class BinaryTree<T> { public T Value { get; set; } public BinaryTree<T> Left { get; set; } public BinaryTree<T> Right { get; set; } public BinaryTree() : this(default, null, null) { } public BinaryTree( T value, BinaryTree<T> left = null, BinaryTree<T> right = null) { Left = left; Right = right; Value = value; } ... }
/// <summary> /// 先序遍歷 /// </summary> /// <param name="node">樹根</param> /// <param name="depth">樹的層樹</param> /// <param name="action">委託, 指望對當前節點執行的操做</param> protected static void PreOrderTraversal( BinaryTree<T> node, int depth, Action<BinaryTree<T>, int> action) { action.Invoke(node, depth); if (node.Left != null) PreOrderTraversal(node.Left, depth + 1, action); if (node.Right != null) PreOrderTraversal(node.Right, depth + 1, action); }
測試代碼:單元測試
[Fact] public void PreOrderTraversalTest() { StringBuilder sb = new StringBuilder(); string result = null; foreach (var d in _data) { d.Item1.PreOrderTraversal( (n, l) => sb.Append($"{n.Value} ")); result = sb.ToString().TrimEnd(); Assert.Equal<string>(result, d.Item2); sb.Clear(); } }
/// <summary> /// 二叉樹前序遍歷非遞歸版本 /// </summary> /// <param name="action">委託, 指望對當前節點執行的操做</param> public void PreOrderTraversalWithoutRecusion2( Action<BinaryTree<T>, int> action) { Stack<NodeWrapper> stack = new Stack<NodeWrapper>(); NodeWrapper wrapper = new NodeWrapper(this, true); stack.Push(wrapper); while(stack.Count > 0) { wrapper = stack.Pop(); action(wrapper.Node, 1); if(wrapper.Node.Right != null) stack.Push(new NodeWrapper(wrapper.Node.Right, true)); if((wrapper.Node.Left != null) && wrapper.FromLeft) stack.Push(new NodeWrapper(wrapper.Node.Left, true)); else if(stack.Count > 0 && wrapper.Node.Right != null) stack.Peek().FromLeft = false; } }
測試代碼相似非遞歸版本, 這裏爲了節省篇幅就不貼了;測試
/// <summary> /// 中序遍歷 /// </summary> /// <param name="node">樹根</param> /// <param name="level">樹的層樹</param> /// <param name="action">委託, 指望對當前節點執行的操做</param> protected static void InOrderTraversal( BinaryTree<T> node, int level, Action<BinaryTree<T>, int> action) { if (node.Left != null) InOrderTraversal(node.Left, level + 1, action); action.Invoke(node, level); if (node.Right != null) InOrderTraversal(node.Right, level + 1, action); }
測試代碼:ui
[Fact] public void InOrderTraversalTest() { StringBuilder sb = new StringBuilder(); string result = null; foreach (var d in _data) { d.Item1.InOrderTraversal( (n, l) => sb.Append($"{n.Value} ")); result = sb.ToString().TrimEnd(); Assert.Equal<string>(result, d.Item3); sb.Clear(); } }
/// <summary> /// 自定義類代替Tuple, 實現不遞歸的中序遍歷, 使用Tuple會致使性能問題 /// (當須要修改棧頂元素的成員變量時, 沒法修改爲員, 只能先出棧->從新建立對象->再入棧)!!! /// </summary> /// <param name="action"></param> public void InOrderTraversalWithoutRecusion3(Action<BinaryTree<T>, int> action) { Stack<NodeWrapper> stack = new Stack<NodeWrapper>(); NodeWrapper wrapper = new NodeWrapper(this, true); stack.Push(wrapper); while (stack.Count > 0) { wrapper = stack.Pop(); if (wrapper.Node.Left != null && wrapper.FromLeft) { stack.Push(wrapper); stack.Push(new NodeWrapper(wrapper.Node.Left, true)); } else { action(wrapper.Node, 1); // 訪問節點 if (wrapper.Node.Right != null) stack.Push(new NodeWrapper(wrapper.Node.Right, true)); else if (stack.Count > 0) stack.Peek().FromLeft = false; } } }
測試代碼相似非遞歸版本, 這裏爲了節省篇幅就不貼了;this
/// <summary> /// 後序遍歷 /// </summary> /// <param name="node">樹根</param> /// <param name="level">樹的層樹</param> /// <param name="action">委託, 指望對當前節點執行的操做</param> protected static void PostOrderTraversal( BinaryTree<T> node, int level, Action<BinaryTree<T>, int> action) { if (node.Left != null) PostOrderTraversal(node.Left, level + 1, action); if (node.Right != null) PostOrderTraversal(node.Right, level + 1, action); action.Invoke(node, level); }
測試代碼code
[Fact] public void PostOrderTraversalTest() { StringBuilder sb = new StringBuilder(); string result = null; foreach (var d in _data) { d.Item1.PostOrderTraversal( (n, l) => sb.Append($"{n.Value} ")); result = sb.ToString().TrimEnd(); Assert.Equal<string>(d.Item4, result); sb.Clear(); } }
/// <summary> /// 二叉樹後序遍歷非遞歸版本 /// </summary> /// <param name="action"></param> public void PostOrderTraversalWithoutRecusion2(Action<BinaryTree<T>, int> action) { Stack<NodeWrapper> stack = new Stack<NodeWrapper>(); NodeWrapper wrapper = new NodeWrapper(this, false); stack.Push(wrapper); while (stack.Count > 0) { wrapper = stack.Pop(); if (wrapper.Node.Left != null && !wrapper.FromLeft) { stack.Push(wrapper); stack.Push(new NodeWrapper(wrapper.Node.Left, false)); } else { if(stack.Count > 0) stack.Peek().FromLeft = true; if (wrapper.Node.Right != null && !wrapper.FromRight) { wrapper.FromRight = true; stack.Push(wrapper); stack.Push(new NodeWrapper(wrapper.Node.Right, false)); } else action(wrapper.Node, 1); } } }
測試代碼相似非遞歸版本, 這裏爲了節省篇幅就不貼了;