3 Hibernate：本地 API 單元測試優化

在 2 Hibernate：入門簡介 中已經介紹瞭如何使用 hibernate 本地 API，根據 Hibernate 官方文檔，對單元測試代碼進行優化。

package hibernate;

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.List;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.boot.MetadataSources;
import org.hibernate.boot.registry.StandardServiceRegistry;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.junit.After;
import org.junit.Before;
import org.junit.Test;

public class NativeApiIllustrationTest {

    private SessionFactory sessionFactory;

    @Before
    public void setUp() throws Exception {
        final StandardServiceRegistry registry = 
            new StandardServiceRegistryBuilder().configure("hibernate.cfg.xml").build();
        try {
            sessionFactory = new MetadataSources(registry).buildMetadata().buildSessionFactory();
        } catch (Exception e) {
            // 若是構建SessionFactory出現異常，須要手動銷燬StandardServiceRegistry
            StandardServiceRegistryBuilder.destroy(registry);
        }
    }

    @After
    public void tearDown() throws Exception {
        if (null != sessionFactory) {
            sessionFactory.close();
        }
    }

    @Test
    public void test() throws ParseException {
        Session session = sessionFactory.openSession();
        session.beginTransaction();
        session.save(new Person("tom", "Tommy", new SimpleDateFormat("yyyy-MM-dd").parse("1985-01-01")));
        session.save(new Person("mix", "Mercy", new SimpleDateFormat("yyyy-MM-dd").parse("1990-10-01")));
        session.getTransaction().commit();
        session.close();

        session = sessionFactory.openSession();
        session.beginTransaction();
        @SuppressWarnings("unchecked")
        List<Person> result = session.createQuery(" FROM Person").list();
        for (Person person : result) {
            System.out.println(person);
        }
        session.getTransaction().commit();
        session.close();
    }

}

打印結果：

Hibernate: 
    insert 
    into
        PERSON
        (ACCOUNT, NAME, BIRTH) 
    values
        (?, ?, ?)
Hibernate: 
    insert 
    into
        PERSON
        (ACCOUNT, NAME, BIRTH) 
    values
        (?, ?, ?)
六月 24, 2017 4:25:44 下午 org.hibernate.hql.internal.QueryTranslatorFactoryInitiator initiateService
INFO: HHH000397: Using ASTQueryTranslatorFactory
Hibernate: 
    select
        person0_.ID as ID1_0_,
        person0_.ACCOUNT as ACCOUNT2_0_,
        person0_.NAME as NAME3_0_,
        person0_.BIRTH as BIRTH4_0_ 
    from
        PERSON person0_
Person [id=1, account=tom, name=Tommy, birth=1985-01-01 00:00:00.0]
Person [id=2, account=mix, name=Mercy, birth=1990-10-01 00:00:00.0]
六月 24, 2017 4:25:44 下午 org.hibernate.engine.jdbc.connections.internal.DriverManagerConnectionProviderImpl stop
INFO: HHH10001008: Cleaning up connection pool [jdbc:mysql://localhost:3306/test]